English translation Invertible matrix (nonsingular matrix), sum of matrix, product of matrix, transpose of matrix, determinant of matrix, block matrix, invertible matrix, identity matrix, zero matrix, inverse matrix, adjoint matrix, elementary matrix, diagonal block matrix

English translation Invertible matrix (nonsingular matrix), sum of matrix, product of matrix, transpose of matrix, determinant of matrix, block matrix, invertible matrix, identity matrix, zero matrix, inverse matrix, adjoint matrix, elementary matrix, diagonal block matrix

Invertible matrix (non singular matrix)
Sum of matrices
Product of matrices
Transpose of matrices
Determinant of matrices
Block matrix-
Invertible matrix
Unit matrix
Zero matrix
Inverse matrix inverse
Adjoint matrix - company matrix
Elementary matrix
Diagonal block matrix - diagonal. Matrix

1.8-3 / 5 x = 3 / 10

1.8-3 / 5 x = 3 / 10
3x of 5 = 1.8-3 of 10
3x = 1.5
X = 1.5 / 3 / 5
x=2.5

What is the sum of the logarithm of the equation with 2 as the base (2-2 ^ x), plus x, plus 99, equal to 0?
The sum of LG2 (2-2 ^ x) + X + 99 = 0 is_______ .

The sum of LG2 (2-2 ^ x) + X + 99 = 0 is - 99. The equation LG2 (2-2 ^ x) + X + 99 = 0 can be reduced as follows: LG2 (2-2 ^ x) = - x-99, i.e. 2-2 ^ x = 2 ^ (- x-99) let 2 ^ x = t, then the above equation can be reduced to: T & # 178; - 2T + 2 ^ (- 99) = 0 by Weida's theorem, T1 * T2 = 2 ^ (x1 + x2) = 2 ^ (- 99), so X1 + x2 = - 99

The surface equation of curve Y-1 = Z rotating around Y axis
It's Y-1 = Z ^ 2

This is a surface of revolution
f（y,z）=0
So the surface of revolution is f (+ - √ (x ^ 2 + y ^ 2), z = 0
So the surface is x ^ 2 + y ^ 2 = (Z ^ 2 + 1) ^ 2

Fractional mixing,
（1）3/11÷（3/4×3/11）
（2）6/5×2/3－2/7÷7/8
（3）5/8×4×1/5
（4）3/7×（1÷2/3）

（1）3/11÷（3/4×3/11）
=3/11÷(3/11)÷(3/4)
=1÷(3/4)
=4/3
（2）6/5×2/3－2/7÷7/8
=4/5 - 2/7×(8/7)
=4/5 - 16/49
=196/245 -80/245
=116/245
（3）5/8×4×1/5
=5/2 ×(1/5)
=1/2
（4）3/7×（1÷2/3）
=3/7 ×(3/2)
=9/14

Let f (x) = LG (4 ^ x-a multiplied by 2 ^ x + 1). When x belongs to (- 00,1), the function is meaningful. Find the value range of A

Let t = 2 ^ x, then

Given 2x ^ 2-2xy + y ^ 2-6x-4y + 27 = 0, find the maximum or minimum value of real number X

That is to say, the quadratic equation of one variable with respect to y has real roots, the discriminant is greater than or equal to 0, and it can be solved

The process of 40 exercises of binary linear equations

1) 66x + 17Y = 3967 25X + y = 1200 answer: x = 48 y = 47 (2) 18x + 23y = 2303 74x-y = 1998 answer: x = 27 y = 79 (3) 44x + 90Y = 7796 44x + y = 3476 answer: x = 79 y = 48 (4) 76x-66y = 4082 30x-y = 2940 answer: x = 98 y = 51 (5) 67x + 54y = 8546 71x-y = 56

Finding the second derivative of a function at the point where the discontinuity can be removed
The first derivative of a function at a point where the discontinuity can be removed can be obtained by comparing the left and right derivatives. How can the second derivative of this point be obtained?

There are some problems in your description: 1) a function has no derivative at the discontinuous point; 2) it is not a removable discontinuous point after the definition of removable discontinuous point is supplemented to make it continuous

It is known that a and B are positive real numbers, a is the mean of the equal difference of AB, and B is the mean of the equal ratio of ab
be
A:ab=AB
C:abAB

Choose C
From the question, we can get 2A = a + B
B^2=ab
∵a>0,b>0
∴a+b≥2√ab
Ψ 2A ≥ absolute value 2B, a ≥ absolute value b
Ψ AB = B ^ 2 ≤ absolute value ab
Choose C