If ABC = 1, then the value of AAB + A + 1 + BBC + B + 1 + CCA + C + 1 is () A. 1B. 0C. -1D. -2

If ABC = 1, then the value of AAB + A + 1 + BBC + B + 1 + CCA + C + 1 is () A. 1B. 0C. -1D. -2


Then AAB + A + 1 + BBC + B + 1 + CCA + C + 1 = AC1 + AC + C + BBC + B + 1 + BC1 + BC + B = ABCB + 1 + BC + BB + B + 1 + BC1 + BC + B = 1 + B + BCB + 1 + BC = 1



Xiao Ming's father works in a joint venture with a monthly salary of 2500 yuan. According to the regulations, 800 yuan is tax-free, and the rest is subject to personal income tax. The taxable part is divided into two parts, which are taxed according to different tax rates, that is, the part not exceeding 500 yuan is taxed at 5%, and the part not exceeding 500 yuan is taxed at 10%?


Taxable part: 2500-800 = 1700 yuan
If it does not exceed 500 yuan, the tax shall be 500 * 5% = 25 yuan
Remaining: 1700-500 = 1200 (yuan) to be taxed
More than 500 yuan but not more than 2000 yuan, tax: 1200 * 10% = 120 (yuan)
Total tax: 120 + 25 = 145 yuan
A:
Xiao Ming's father has to pay personal income tax 145 yuan per month



There are three kinds of goods of a, B and C. If you buy 3 pieces of a, 7 pieces of B and 1 piece of C, it costs 315 yuan in total. If you buy 4 pieces of a, 10 pieces of B and 1 piece of C, it costs 420 yuan in total. How much is one piece of a, B and C?


This problem assumes that the unit price of a is X Yuan and that of B is y yuan, and then subtract the former from the latter to get 3Y + x = 105. This is a quadratic equation of 2 yuan. We can get the unit price of a and B, and then take it to any one of the formulas to find C



There are 24 boys and 20 girls in Grade 6 (1) class of sunshine primary school. How many percent more boys than girls?


There are more boys than girls
(24-20)÷20×100%
=4÷20×100%
=20%



The third power of √ 24 - √ 0.5 + 2 √ (3 / 2) + 1 / 18 - (- √ 23)


The third power of √ 24 - √ 0.5 + 2 √ (3 / 2) + 1 / 18 - (- √ 23)
=2√6-1/2√2+√6+1/6√6+3/4√6
=47/12√6-1/2√2



The mother monkey picked back some peaches. The little monkeys ate half of these peaches on the first day and the remaining one-third on the second day. At this time, there are still 20 peaches left. How many peaches do they pick?
Quantity relation


Methods the formula of one column 20 △ 1-1 / 3 △ 1-1 / 2 = 20 △ 2 / 3 △ 1 / 2 = 20 × 3 / 2 × 2 = 3 - × 2 = 60 notes: 20 △ 1-1 / 3 represents the peach left after eating half of the first time, and then △ 1-1 / 2 represents all the peaches



The sixth power of (a-b) / (the third power of (a-b) / (B-A)


Original form
=(a-b)^6÷(a-b)^3÷[-(a-b)]
=-(a-b)^(6-3-1)
=-(a-b)²



The distance between the two places is 420 kilometers. Two cars drive from place a to place B at the same time. The first car travels 42 kilometers per hour, and the second car travels 28 kilometers per hour
How many hours does it take for the two cars to meet each other?


Let two cars share x hours from departure to meeting
X*(42+28)=420*2
70X=840
X=840/70
X=12
The two cars share 12 hours from departure to meeting



Equation: x + (52 + x) = 72


The result of removing brackets is: 2x = 72-52
2x=20
x=10
It's easy



1. The distance between the two places is 360km. The train and the bus leave from the two places at the same time. They run in opposite directions and meet each other in 4H. The speed of the train and the bus is 4:5, and the speed of the two cars is 4:5
How many meters per hour
2. Four children of a, B, C and D donated to the disaster area. It is known that a donated 100 yuan less than B. the amount of donation of a is two-thirds of that of the other three. The amount of donation of B is one-quarter of that of the other three. The amount of donation of C is four-thirds of that of the other three?
3. 80t is one third more than () t
4. X + 2 / 7 x = 3 / 4
5. X - one fifth x = three tenths
The formula of practical problems


1.360/4/(4+5)=10 10*4=40 10*5=50
2. A: 13 + 2 / 2, B 4 + 1 / 100 / (2 / 15 + 1 / 5) = 300 * 2 / 15 = 40 + 100 = 140
3.80/(1+1/3)=60
4.x+2/7x=3/4
9/7x=3/4
x=3/4* 7/9
x=7/12
5.x-1/5x=3/10
4/5x=3/10
x=3/10 *5/4
x=3/8