A rectangular sheet of iron, 26 cm in length and 16 cm in width, is cut off from its four corners. The square with a side length of 3 cm is then welded into an open iron box. How many ml is the volume of this iron box?

A rectangular sheet of iron, 26 cm in length and 16 cm in width, is cut off from its four corners. The square with a side length of 3 cm is then welded into an open iron box. How many ml is the volume of this iron box?


1 cubic centimeter = 1 ml, (26-3 × 2) × (16-3 × 2) × 3, = 20 × 10 × 3, = 600 (cubic centimeter), 600 cubic centimeter = 600 ml, answer: the volume of this iron box is 600 ml



A 50 cm long, 40 cm wide rectangular sheet iron, in the four corners of each cut out a side length of 6 cm square, made into a rectangular iron box, the volume of this box is how much?


The height of the box is 6cm
Length: 50-6 × 2 = 38 cm
Width: 40-12 = 28cm
therefore
Volume = 38 × 28 × 6 = 6384 CC



The bottom of a rectangle is a square. Expand the side of the rectangle to form a square with a circumference of 80 cm. Calculate the volume of the rectangle


Cuboid volume = base area * height
If the perimeter is 80 cm, the side length can be found to be 20 cm. That is to say, the height of the cuboid is 20 cm. 20 / 4 = 5, and the side length of the bottom surface is 5 cm, so the bottom area is 25 square cm
So the answer is 25 * 20 = 500 cubic centimeters



What is the surface area of a rectangular box with a square bottom, a circumference of 80 cm and a height of 50 cm


A cuboid with a square bottom has a circumference of 80 cm and a square bottom has a side length of 80 △ 4 = 20 cm,
The surface area of cuboid carton is 20 × 20 × 2 + 20 × 50 × 4 = 8800 square centimeter



There is a cuboid with a height of 5 cm, and the total area of its side is 80 square cm. What is the circumference of the bottom of the cuboid?
The side refers to the left and right sides


80÷ 2 =40
40 ÷5 =8
(40 +8 )×2 =96



The utility model relates to a rectangular water tank without a cover, the bottom area of which is a square with a circumference of 160 cm and a height of 80 cm. How many square meters of iron sheet is needed at least to make such a water tank?


The side length of the bottom surface is 160 △ 4 = 40 cm
Iron sheet required = 40x40 + 40x80x4 = 14400 square centimeter = 1.44 square meter



The length is 80 cm, the width is 60 cm rectangle, the four corners are cut into four identical small squares, and the four sides are folded to form a box with a bottom area of 1500 square cm
The faster the better, to find the side length of a small square
What does the preceding respondent "*" mean


Let the side length of the cut small square be x cm
Then: 80 * 60-2 * 80x-2 * 60x + 4x ^ 2 = 1500
4x^2-280x+4800-1500=0
x^2-70x+825=0
If we solve this quadratic equation with one variable, we get
X1 = 55 (rounding off)
x2=15
Therefore, the square with a side length of 15 cm should be cut off



With a piece of 80cm long and 60cm wide steel sheet, four small squares with the same side length of xcm are cut off at four corners, and then they are made into a cuboid box with a bottom area of 1500cm2 without a cover. In order to find out x, according to the equation of the title, we can get ()
A. x2-70x+825=0B. x2+70x-825=0C. x2-70x-825=0D. x2+70x+825=0


Four small squares with the same side length of xcm are cut off at four corners. The length of the bottom of the box is 80-2x, the width is 60-2x, and the bottom area is 1500cm2. So (80-2x) (60-2x) = 1500, and the result is: x2-70x + 825 = 0, so select: a



Cut off a rectangular strip 2 cm wide from the square iron sheet, and the remaining area is 80 square centimeters. What is the side length of the original square iron sheet?


8



A cuboid is 26 cm high. It is cut into two cuboids horizontally. The surface area is increased by 80 square cm


80 △ 2 × 26, = 40 × 26, = 1040 (cubic centimeter); answer: the original cuboid volume is 1040 cubic centimeter