Solve two equations and two calculations (answer, process, formula. Be correct. Write clearly) 1.（x+8)*50=(x-5)*60 2.x+(4x-4)=(4x-4)=96-28 1. The greatest common factor of two numbers is 8 and the least common multiple is 96. One of them is 24. What is the other number? 2. How many beans are there in a pile of five more than three, six more than four, seven more than five?

Solve two equations and two calculations (answer, process, formula. Be correct. Write clearly) 1.（x+8)*50=(x-5)*60 2.x+(4x-4)=(4x-4)=96-28 1. The greatest common factor of two numbers is 8 and the least common multiple is 96. One of them is 24. What is the other number? 2. How many beans are there in a pile of five more than three, six more than four, seven more than five?

1. (x + 8) * 50 = (X-5) * 60, 50x + 400 = 60x-300, 10x = 100, x = 102. If the question is wrong, please check. 1. 96 * 8 / 24 = 32 2. If you put two more beans in it, it's just the common multiple of 5, 6 and 7, so you can find the least common multiple of 5.6.7 and subtract 2

Observe the following equation (!) x + 2 / x = 3; (2) x + 6 / x = 5; (3) x + 12 / x = 7, then x + n ^ 2 + n / x-3 = 2n + 4, X1 = () x2 = ()

The previous equation can be summarized as
x+(n²+n)/x=2n+1
Obviously, the solution is x = n or N + 1,
that
x+(n²+n)/(x-3)=2n+4
Namely
(x-3)+(n²+n)/(x-3)=2n+1
therefore
X-3 = n or N + 1
That's the solution
X = n + 3 or N + 4