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In △ ABC, ab = 1, AC = radical 2, angle B = 45 °, find the length of BC and the area of △ ABC
BC = 3 / 2 under root + 1 / 2 under root!
The area is equal to (1 / 2 under BC * radical) / 2
I forgot how to calculate the root sign. I want to make the auxiliary line of a perpendicular to BC. According to the true angle triangle a + B = C and 45 ° right triangle, I can calculate it
In △ ABC, ∠ B = 30 & # 186;, ab = 2 √ 3, AC = 2, then the area of △ ABC is
According to the sine theorem
sinC=(AB/AC)*sinB=√3/2
So C = 60 degrees
A=180°-C-B=90°
Area of △ ABC = (AB * AC) * / 2 = (2 √ 3) * 2 / 2 = 2 √ 3
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