The abscissa of the intersection of line Y1 = K1X + B1 and line y2 = k2x + B2 is a, if K1
When x = a
y1=y2
Suppose that Y1 = y2 = M
k1a,y10
So Y2 and X increase
So x > a
y2>m
So Y1
It is known that the intersection of the image of the first-order function y = K1X + B (K1 ≠ 0) and the positive scale function y = k2x (K2 ≠ 0) is a (4,3), and the intersection of the image and the Y axis is B (0, - 3)
(1) The analytic expressions of positive proportion function and linear function are obtained;
(2) Find the area of △ AOB
(1) Because the intersection of the image of y = K1X + B (K1 ≠ 0) and the y-axis is B (0, - 3), so B = - 3, y = k1x-3, and because the intersection of the image of y = k1x-3 (K1 ≠ 0) and the positive scale function y = k2x (K2 ≠ 0) is a (4,3), so 4k1-3 = 3, K1 = 3 / 2, 4k2 = 3, K2 = 3 / 4, so the primary function of the positive scale function y = 3 / 4 * x, y = 3 / 2 * x-3
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