Parabola y = - 4 (x + 3) square, when x_____ The value of function y increases with the increase of X_____ The value of function y decreases with the increase of X, and the square of parabola y = - 4 (x + 3) can be changed from the plane direction of parabola y = - 4x_____ Translation_____ Units get it!

Parabola y = - 4 (x + 3) square, when x_____ The value of function y increases with the increase of X_____ The value of function y decreases with the increase of X, and the square of parabola y = - 4 (x + 3) can be changed from the plane direction of parabola y = - 4x_____ Translation_____ Units get it!


Parabola y = - 4 (x + 3) square, if__ x≤ -3__ When x ≥ - 3, the function value y increases with the increase of X_____ The value of function y decreases with the increase of X, and the square of parabola y = - 4 (x + 3) can be changed from the plane direction of parabola y = - 4x___ Left_ Translation___ 3__ Units get



It is known that the vertex coordinate e (1,0) of the parabola ax ^ 2 + BX + C and the intersection coordinate of Y axis are (0,1)
(1) , find the function relation of parabola. (y = x ^ 2-2x + 1)
(2) Let a and B be two moving points on the x-axis, and the distance AB is 4. Let ad be perpendicular to the x-axis, BC be perpendicular to the x-axis, and the parabola intersect D and C. let a coordinate (T, 0) and the area of the quadrilateral ABCD be s
1. Find the function relation between S and T, and find out what quadrilateral ABCD is when s is the smallest?
2. When s is the minimum, find a point P on the diagonal BD, which is the minimum perimeter of the triangle PAE, and find the coordinates of P


(1) Because the vertex coordinate e (1,0) let y = a (x-1) ^ 2, because the function passes through (0,1), so 1 = a (0-1) ^ 2, the solution is: a = 1, so y = (x-1) ^ 2, that is y = x ^ 2-2x + 1 (2) if point a (T, 0), then point B (T + 4,0), so point d (T, y) y = (t-1) ^ 2, point d (T, (t-1) ^ 2) the same as point C (T + 4, (T + 4-1) ^ 2), that is (T + 4, (...)



It is known that the parabola y is equal to AX square plus BX plus C, passing through (0,1), and the vertex coordinate is (2. - 1)


Let the analytic expression of quadratic function be y = a (X-2) ^ 2-1
Substituting (0,1) into
1=4a-1
Then a = 1 / 2
So y = 1 / 2 (X-2) ^ 2-1
=1/2*x^2-2x+1
I hope my answer can help you,
In the upper right corner of my answer, click [adopt answer],



The vertex of the parabola y equals ax square plus BX plus C is an intersection point of D (- 1,2) and Y axis between (- 2,0) (- 3,0),
Which is right
1.b 2-4ac