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Square of (x + 2Y) (x-2y) - (2x-y) + (3x-y) (2x-5y) where x = - 1, y = 1 / 13
Original formula = x ^ 2-4y ^ 2 - (4x ^ 2-4xy + y ^ 2) + 6x ^ 2 + 5Y ^ 2-2xy-15xy = 3x ^ 2-13xy
When x = - 1, y = 1 / 13, the original formula = 3 + 1 = - 2
It is known that the quadratic power of 5y-2y + 6 is equal to 8, so what is the quadratic power of [5y-2y] + 1 equal to
Big God solution
∵5y²-2y+6=8
∴5y²-2y=8-6=2
（5y²-2y)²+1
=2²+1
=5
On the square ratio of X, 100 equals 1 on the square ratio of 36-y, which means hyperbola. What is the value range of X? What is the value range of Y?
x^2/36-y^2/100=1,
x^2/36=y^2/100+1≥1,
So x ^ 2 ≥ 36,
X ≥ 6 or X ≤ - 6
The hyperbolic equation with a focal length of 8 and a common asymptote with hyperbola X25 − Y23 = 1 is______ ．
Let the equation of hyperbola be x2a2 − y2b2 = ± 1. According to the meaning of the question, the equation of a = 10 and B = 6 for hyperbola is: x210 − y26 = ± 1. So the answer is: x210 − y26 = 1 or x210 − y26 = − 1
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