5 / 12 * 19 * (3 / 38) * 6 =? Formula calculation

5 / 12 * 19 * (3 / 38) * 6 =? Formula calculation

15/4

A simple formula of 8 / 19 × 12 × 38

8/19×12×38
= 8/19×38x12
=16x12
=16x10+16x2
=160+32
=192
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Put the natural numbers 1, 2, 3 998999 is divided into three groups. If the average of each group is exactly equal, then the sum of the three averages is______ ．

1+2+3+… +998 + 999 = (1 + 999) × 999 △ 2 = 500 × 999, the sum of each group is: 500 × 999 △ 3 = 500 × 333, the average of each group is: 500 × 333 △ 333 = 500, then the sum of the average of the three groups is: 500 × 3 = 1500 answer: the sum of the three average is 1500, so the answer is: 1500

Put the natural numbers 1, 2, 3 998999 is divided into three groups. If the average of each group is exactly equal, then the sum of the three averages is______ ．

1+2+3+… +998 + 999 = (1 + 999) × 999 △ 2 = 500 × 999, the sum of each group is: 500 × 999 △ 3 = 500 × 333, the average of each group is: 500 × 333 △ 333 = 500, then the sum of the average of the three groups is: 500 × 3 = 1500 answer: the sum of the three average is 1500, so the answer is: 1500

Put the natural numbers 1, 2, 3 998999 is divided into three groups. If the average of each group is exactly equal, then the sum of the three averages is______ ．

1+2+3+… +998 + 999 = (1 + 999) × 999 △ 2 = 500 × 999, the sum of each group is: 500 × 999 △ 3 = 500 × 333, the average of each group is: 500 × 333 △ 333 = 500, then the sum of the average of the three groups is: 500 × 3 = 1500 answer: the sum of the three average is 1500, so the answer is: 1500

There are three natural numbers ABC, known AB = 30, AC = 42, BC = 35, find a + B + C = how much

AB = 30 = 5*6
BC = 35 = 5*7
CA = 42 = 7*6
Obviously only C = 7
So a = 6, B = 5
A + B + C = 6 + 5 + 7 = 18

There are three natural numbers a, B and C. given a × B = 34, B × C = 35 and a × C = 42, what is the product of ABC?

A * b = 30? ABC = 210

In known natural numbers a, B and C, what are a × B = 16, a × C = 12, a, B and C respectively? Write all the answers

According to a × B = 16, a × C = 12, we can get that a is both the factor of 16 and the factor of 12, because the common factors of 16 and 12 are: 1, 2 and 4, so the value of a is: 1, 2 and 4; (1) when a = 1, B = 16 △ 1 = 16, C = 12 △ 1 = 12; (2) when a = 2, B = 16 △ 2 = 8, C = 12 △ 2 = 6; (3) when a = 4, B = 16 △ 4 = 4, C = 12 △ 4 = 3; in conclusion, we can get a = 1b = 16C = 12, a = 2B = 8C = 6 or a = 4B = 4C = 3

ABC each represents a natural number. If a times b equals 20, B times C equals 30, and C times a equals 24, then what are ABC respectively?

a=4,b=5,c=6

There are three natural numbers ABC, the average of AB is 24, the average of BC is 30, and the average of AC is 42
How to find the average of a, B and C

This kind of problem is very easy to calculate. LZ should not be confused by AB / BC / AC. according to the description of the problem, first list: the average number of AB is 24, that is, a + B = 24 * 2 = 48, the average number of BC is 30, that is, B + C = 30 * 2 = 60, the average number of AC is 42, that is, a + C = 42 * 2 = 84