{4x-4y-1 = 0 {3x-2-6y + 3 = 1}
(1) 1 / 4 x-4 / 3y-1 = 0 X / 4 - (3y-1) / 4 = 0 (finishing) (both sides at the same time × 4) x-3y + 1 = 0 (3) x = 3y-1 (2) 3 / 3 x-2-6 / 5Y + 3 = 1 (X-2) / 3 - (5Y + 3) / 6 = 1 (finishing, at the same time × 6) 2 (X-2) - (5Y + 3) = 62x-4-5y-3 = 6 (transfer) (4) 2x-5y = 13
X = 3Y 2x-y = 15 to solve equations
Substituting (1) into (2) leads to
6y-y=15
∴5y=15
y=3
Substituting y = 3 into (1) yields
x=9
The solution of the system of equations is
x=9
y=3
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