Judge whether the following groups of functions are equal (1) f (x) = √ (X-2) &# 178;, G (x) = X-2 Judge whether the following groups of functions are equal (1) f(x)=√(x-2)²,g(x)=x-2 (2) F (x) = (X & # 178; + 1) of (X & # 178; + x), G (x) = x

Judge whether the following groups of functions are equal (1) f (x) = √ (X-2) &# 178;, G (x) = X-2 Judge whether the following groups of functions are equal (1) f(x)=√(x-2)²,g(x)=x-2 (2) F (x) = (X & # 178; + 1) of (X & # 178; + x), G (x) = x

(1) If X-2 is not negative, then f (x) = X-2; if X-2 is not positive, then f (x) = - x + 2
(2) The denominator of F (x) cannot be reduced to X

How is lg9 / Lg3 calculated? Why are LG4 / LG2 the same?

lg9/lg3 = lg(3^2)/lg3 = 2*lg3/lg3 = 2
lg4/lg2 = lg(2^2)/lg2 = 2*lg2/lg2 = 2

LG1 LG2 Lg3 LG4 or LG1 LG10 LG100 lg1000, which is the arithmetic sequence
Write a why

∵ lg1=0
lg10=1
lg100=2
lg1000=3
∴ lg1000-lg100=lg100-lg10=lg10-lg1=l
{LG1, LG10, LG100, lg1000 are arithmetic sequences
But lg2-lg1 ≠ lg3-lg2
{LG1, LG2, Lg3, LG4 are not arithmetic sequences

Why is (Lg3 / LG4) × (LG2 / lg9) equal to 1 / 4

(lg3 /lg4)×(lg2 /lg9)
=[lg3/(lg2^2)×(lg2/lg3^2)
=[lg3/(2lg2)]×[lg2/(2lg3)]………… Both LG2 and Lg3 can be divided
=1/4