First simplify, then calculate: 6A + 2A & sup2; - 3A + A & sup2; + 1, a = - 5 - 3 / 2a-5 / 6A + 1 / 3b-1 / 6B, a = 2, B = 6, 3ab-4 / 5x-4ab, x = 5, a = 1 / 3, B

First simplify, then calculate: 6A + 2A & sup2; - 3A + A & sup2; + 1, a = - 5 - 3 / 2a-5 / 6A + 1 / 3b-1 / 6B, a = 2, B = 6, 3ab-4 / 5x-4ab, x = 5, a = 1 / 3, B

1. Simplification result: 1 + 3 A + 3 A ^ 2, calculation result: 61
2. Results of simplification: 1 (- 14 A + b) / 6, results of calculation: - (11 / 3)
3. Simplification result: - B / 3-4
Ha ha, your last question didn't give the result of B. I'll substitute the result of B into the calculation

（3a2-2a-5）+（______） =a2-7a+9．

A2-7a + 9 - (3a2-2a-5) = - 2a2-5a + 14, so the missing item should be: - 2a2-5a + 14

Calculation: (a ^ 2-8a + 16) / (9-A ^ 2) / (16-a ^ 2) / (9 + 6A + A ^ 2)

The original formula = (A-4) &# 178; / (a + 3) (A-3) / [- (a + 4) (A-4) / (a + 3) &# 178;] = (A-4) &# 178; / (a + 3) (A-3) × (a + 3) &# 178; / (a + 4) (A-4) = - (A-4) / (A-3) × (a + 3) / (a + 4) = (- A & # 178; + A + 12) / (A & # 178; + 4a-12)

9 × 122 & sup2; - 4 × 133 & sup2; by factorization
RT

Using the square difference formula: A & sup2; - B & sup2; = (a + b) (a-b)
9×122²-4×133²
=3²×122²-2²×133²
=（3×122）²-（2×133）²
=366²-266²
=（366+266)×（366-266）
=632×100
=63200