As shown in the figure, the parabola y = AX2 + BX + C passes through three points a (- 1,0) B (3,0) C (0,3), the axis of symmetry intersects the parabola at point P, and intersects the straight line BC at point m, connecting Pb 1. Find the analytical formula of the parabola 2. Whether there is a point Q on the parabola, so that the area of △ QMB and △ PMB is equal. If there is, find the coordinate of point Q; if not, explain the reason 3. Whether there is a point R on the parabola on the right side of the symmetry axis in the first quadrant, so that the area of △ rpm and △ RMB is equal. If there is, write the coordinates of point R directly Graph in space

As shown in the figure, the parabola y = AX2 + BX + C passes through three points a (- 1,0) B (3,0) C (0,3), the axis of symmetry intersects the parabola at point P, and intersects the straight line BC at point m, connecting Pb 1. Find the analytical formula of the parabola 2. Whether there is a point Q on the parabola, so that the area of △ QMB and △ PMB is equal. If there is, find the coordinate of point Q; if not, explain the reason 3. Whether there is a point R on the parabola on the right side of the symmetry axis in the first quadrant, so that the area of △ rpm and △ RMB is equal. If there is, write the coordinates of point R directly Graph in space


1A (- 1,0) B (3,0) C (0,3) X1 = - 1, X2 = 3, x = 0, y = C = 3x1x2 = C / a = - 3A = - 1x1 + x2 = 2 = - B / AB = 2Y = - x ^ 2 + 2x + 3 symmetry axis X = - B / 2A = (x1 + x2) / 2 = 1, C-B ^ 2 / 4A = 3-4 / (- 4) = 4 vertex P (1,4) straight line BC: Y-3 = [(3-0) / (0-3)] xy = - x + 3x = 1, y = 2m (1,2) P (1,4) 2 through P parallel BC



As shown in the figure, in the plane rectangular coordinate system, point a (- 3,0), B (0,6), C (0,1), D (2,0), find the intersection of line AB and line CD
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Let a (- 3,0), B (0,6) be substituted into the analytic expression of the line AB to obtain {- 3k1 + B1 = 0b1 = 6 solution to obtain: {K1 = 2B1 = 6} the analytic expression of the line AB is y = 2x + 6, let the analytic expression of the line CD be y = k2x + B2, and substitute C (0,1), D (2,0) into the analytic expression of the line CD to obtain {B2 = 12k2 + B2 = 0 solution to obtain: {K2 = - ## - 189; B2 = 1} the analytic expression of the line CD is y = k2x + B2



In the plane rectangular coordinate system, the coordinates of points a, B, C and D are shown in Figure 6, and the intersection coordinates of line AB and line CD are obtained


A (- 3,0), B (0,6); C (0,1), D (2,0) so let the analytic expression of AB be y = KX + B, then a is x = - 3, when y = 0, the equation (1) 0 = - 3K + B can be obtained; B is x = 0, when y = 6, the equation (2) 6 = 0 + B can be obtained; from (1) (2) simultaneous equations, k = 2, B = 6 can be obtained, so the analytic expression is y = 2x + 6, similarly, the analytic expression of straight line CD is y = - 1 / 2x + 1, and the two analytic expressions can be obtained as the equations, x = - 2, The value of y = 2 is the intersection coordinate (- 2,2)



As shown in the figure, in the plane rectangular coordinate system, point a (- 3,0), B (0,6), C (0,1), D (2,0), find the intersection of line AB and line CD


Write AB linear expression: (y-6) = 2x; CD expression: y = - 1 / 2 (X-2): simultaneously get x = - 2, y = 2
The answer is (- 2,2)