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1. The tangent equation of curve y = ln x passing through point (1,0) is?
y=ln x
y'=1/x
So the slope of the tangent passing through point (1,0) is k = 1 / 1 = 1
The equation is y = 1 * (x-1) = X-1
What is the tangent equation passing through the point m (E, 1) on the curve y = ln x?
y'=1/x
y'(e)=1/e
So the tangent equation: y = 1 / E (x-e) + 1
That is y = x / E
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