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Judge the graph represented by the following equation, why x ^ + y ^ = 0 x ^ + y ^ - 2x + 4y-6 = 0 x ^ + y ^ + 2ax-b ^ = 0
Are you asking this? 1. X & sup2; + Y & sup2; = 0 means the origin (0,0) 2, X & sup2; + Y & sup2; - 2x + 4y-6 = 0, that is, (x-1) & sup2; + (y + 2) & sup2; = 11 means the circle with (1, - 2) as the center and √ 11 as the radius. 3. X & sup2; + Y & sup2; + 2ax-b & sup2; = 0 means (x + a) & sup2; + Y & sup2; = A & sup
Given that the point a (- 1,1) is in the circle 2x ^ 2 + 2Y ^ 2 + kx-2y + (5K / 8) = 0, find the value range of K
Point a (- 1,1) is in the circle 2x & sup2; + 2Y & sup2; + kx-2y + (5K / 8) = 0
2·(-1)²+2·1²+k·（-1)-2·1+(5k/8)＜0
That is, 2-3K / 8 = 0, k = 16 / 3
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