(-2)2008x（-1/2）2008

(-2)2008x（-1/2）2008

(-2)^2008x（-1/2）^2008
=(2x1/2)^2008
=(1)^2008
=1

The solution of the equation x * = 2008x is——

x²-2008x=0
x(x-2008)=0
x=0,x=2008

The polynomial (A & # 178; - 4) x & # 179; - (A-2) x & # 178; + X-7 is about the quadratic trinomial of A
emergency
5555555555，

The coefficient of quadratic trinomial must be 0, so
A & # 178; - 4 = 0 and
A-2 is not equal to 0
The solution is that when a = 2, a = - 2, a = 2, A-2 = 0, so a = - 2

If the polynomial (A & # 178; - 4) x & # 179; - (A-2) x & # 178; + X-7 is a binomial expression of X, the value of a is obtained

It's about the quadratic trinomial of X, a square minus 4 equals 0, a equals plus or minus 2. And a minus 2 does not equal 0, so a is not equal to 2, and finally a equals - 2

If | 2008 − a | + a − 2009 = a, then a-20082=______ ．

From the meaning of the question, a-2009 ≥ 0, then a ≥ 20092008-a < 0, simplify the original formula, get: A-2008 + a − 2009 = a, namely a − 2009 = 2008, then a-2009 = 20082, namely a-20082 = 2009

X = 2008, y = 2006, find the value of [2x [x ^ 2y-xy ^ 2] + XY [2xy-x ^ 2] / x ^ 2Y

The original formula = (2x & sup3; y-2x & sup2; Y & sup2; + 2x & sup2; Y & sup2; - X & sup3; y) △ X & sup2; y
=x³y÷x²y
=x
=2008

X ^ 2 + y ^ 2 + x ^ 2Y ^ 2-4xy + 1 = 0, find the value of (X-Y) ^ 2008 - (XY) ^ 2008

X^2+Y^2+X^2Y^2-4XY+1=0
(X^2+Y^2-2XY)+(X^2Y^2-2XY+1)=0
(X-Y)^2+(XY-1)^2=0
X-Y = 0
xy-1=0,xy=1
(X-Y)^2008-(XY)^2008
=0^2008-1^2008
=0-1
=-1

Polynomial ax to the fifth power plus BX to the third power plus CX minus five when x is equal to two, the value is equal to seven find the value of polynomial when x is equal to negative two

Ax to the fifth power plus BX to the third power plus CX minus five when x equals two, the value equals seven
Ax fifth power plus BX third power plus CX = 12
Find a polynomial when x is negative two
Ax fifth power plus BX third power plus CX = - 12
Ax quintic plus BX cubic plus CX minus five = - 17

When x = minus 3, the fifth power of ax minus the third power of BX plus CX minus 6 equals 17. When x = 3, the value of this polynomial is

-29

You answer me a question: given that when x = negative 2, the 5th power of the polynomial ax + the 3rd power of BX + CX minus 1 = 5, then when x = 2, what is the above formula equal to

Note that 2 ^ 5 = - (- 2) ^ 5,2 ^ 3 = - (- 2) ^ 3,2 = - (- 2)
So when x = 2, the above formula = - 6-1 = - 7