The solution equation: x2-5x-6 = 0

The solution equation: x2-5x-6 = 0

X2-5x-6 = 0, ∧ (X-6) (x + 1) = 0, ∧ X-6 = 0 or x + 1 = 0, ∧ X1 = 6, X2 = - 1

The solution set of X & # 178; - 5x + 6 = 0
x-2)*(x-3)=0
So X-2 = 0 or x-3 = 0
How does x & # 178; - 5x + 6 = 0 evolve into (X-2) * (x-3) = 0
No math,

X² -5X+6=0
X² - (2+3)X + 6 = 0
X² - 2x - 3X + 6 = 0
(X² - 2x) + (-3X + 6) = 0
x(x-2) - 3(x-2) = 0
(x-2) * (x-3) = 0

x²-x-6/x-1≥0

(x-3)(x+2)/(x-1)≥0
That is, (x-3) (x + 2) (x-1) ≥ 0
Zero is - 2, 1, 3
The denominator is not equal to 0
So x ≤ - 2,1