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1. Positive scale function y = 1 / 2x_____ The value of quadrant y decreases with the decrease of X_____ 2. If the image with positive scale function y = KX (k is not equal to 0) passes through the point (1 / 3, - 1 / 2), then the image passes through the point______ Quadrant, K=______ 23. If the image with positive scale function y = x / m-2 passes through the second and fourth quadrants, the value range of M is________
、y=2/x
2、
A(2,1)
B(1,2)
Symmetric point a '(2, - 1) of a
The line passing a 'and B intersects the x-axis at
P（5/3,0）
The function image y = 3x ^ 2-5x + 4 moves up two units of length. Why is the answer y = 3x ^ 2-5x + 4 + 2 instead of Y + 2 = 3x ^ 2-5x + 4?
sit back and wait
Translation up 2 unit lengths
Let a point (a, b) be on the image of the original function
B = 3A ^ 2-5A + 4
Move up two units
So this point becomes (a, B + 2)
Then B + 2 = 3A ^ 2-5A + 4
To satisfy the equilibrium of the equation, it must be + 2 on the right side of the equation
We get B + 2 = 3A ^ 2-5A + 4 + 2
In this case, the analytic expression of the function becomes
y=3x^2-5x+4+2
The function image is used to solve x, and the written calculation test is: (1) 5x-3 = x + 2; (2) 0.5x-4 = 3x + 2
(1) 5x-3 = x + 2, sort out and get the image of 4x-5 = 0 and function y = 4x-5 as shown in the figure below. From the image, we can see that the coordinates of the intersection of the line y = 4x-5 and the X axis are (54, 0), so the solution of the equation 5x-3 = x + 2 is x = 54. Test: substitute x = 54 into the left and right sides of the equation, and get the left = 5 × 54-3 = 134, right = 54 + 2 = 134, ∵ left = right, ∵ x = 54 is the solution of the equation 5x-3 = x + 2; (2) 0.5x-4 = 3x + 2 The image of 2.5x + 6 = 0 and the function y = 2.5x + 6 is shown in the figure below. From the image, we can see that the coordinates of the intersection of the straight line y = 2.5x + 6 and the X axis are (- 2.4, 0), so the solution of the equation 0.5x-4 = 3x + 2 is x = - 2.4
Use the function image to find the solution of the following equation:
（1）2x+6=0 （2）4x+5=9 （3）-2x+7=-2 （4） 5x-1=2x+5
Find the abscissa of the intersection point with the x-axis, but first write it as a function by moving the direction
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