(4x & # 178; - Y & # 178;) △ 4x & # 178; - 4xy + Y & # 178; / 2x-y process 4X & # 178; - Y & # 178; is an integral, and 4x & # 178; - 4xy + Y & # 178; / 2x-y is an integral

(4x & # 178; - Y & # 178;) △ 4x & # 178; - 4xy + Y & # 178; / 2x-y process 4X & # 178; - Y & # 178; is an integral, and 4x & # 178; - 4xy + Y & # 178; / 2x-y is an integral

(2x-y)(2x+y) ÷[(2x-y)²/(2x-y)]
=(2x-y)(2x+y) ÷(2x-y)
=2x+y

Given 2x-y = 4, find the value of 4x2-4xy + y2-2x + y-6

∵2x-y=4，∴4x2-4xy+y2-2x+y-6=（4x2-4xy+y2）-（2x-y）-6=（2x-y）2-（2x-y）-6=16-4-6=6．

Find x (1) 16x & # 178; - 25 = 0 (2) x & # 178; + 1 = 1.01 (3) (4x-1) & # 178; = 225 (4) 125x & # 179; = 8 (5)
(- 2 + x) & #179; = - 216 seek the great God

1.x=±5/4
2.x=±0.1
3. X = 4 or - 3.5
4.x=2/5
5.x=-4

If X & # 178; - 4x + 3 = 0, then (x-1) &# 178; - 2 (1 + x)=

The equation is x = 1 or 3
Put it in the following formula = - 4