Solving equation 5x ^ 2-x-12 / 5 = 0

The original equation can be reduced to:
（5x-4）*（x+3/5）=0
X 1 = 4 / 5
x2=-3/5

The solution equation: 12 ÷ (0.5x-4) = 6

0.5x-4=12÷6
0.5x=2+4
x=6÷0.5
x=12

Solve the equation, remove the bracket, remove the denominator 5x-1 / 4 = 3x + 1 / 2-2-x / 3

（ 5x-1）/4=（3x+1）/2-（2-x）/3
15x-3=18x+6-8x+4
5x=13
x=13/5

The denominator of the fractional equation 1 - {5x + 2 / X (x + 1)} = 3 / x + 1 is removed

Double x (x + 1)
x(x+1)-(5x+2)=3x
x²+x-5x-2=3x
So x & # 178; - 7X-2 = 0

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