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Solve inequality 1,3 [X-2 (x-1)] ≤ 4x 2,2-2 of X + 4 > 1-3 of X
3（x-2x+2）≤4x
-3x+6≤4x
6≤7x
x≥6/7
12-3x-12＞2-2x
-3x＞2-2x
-x＞2
x＜-2
The system of inequalities 4x + 3Y + 8 ﹥ 0x ﹤ 0y ﹤ 0 indicates that the integral point coordinates in the plane region are ()
A. （-1，-1）B. （-1，0）C. （0，-2）D. （-1，-2）
Because it requires the whole point coordinates in the plane area, it must meet the following requirements: x < 0, y < 0: exclude B and C; combined with: 4x + 3Y + 8 > 0, exclude D. therefore, only answer a meets the requirements
When m is a value, the inequality system 4x + 3M = 2, 8x-3y = m satisfies x > 0, y
4x+3m=2
4x=2-3m
x=(2-3m)/4
When x > 0, (2-3m) / 4 > 0
2-3m>0
3m
To solve the system of inequalities. The range of values of (1) 3x + 2Y = P + 1, (2) 4x + 3Y = P-1, Y > x, P
Well, I want the process and thinking of solving the problem to be either not able to solve, or I feel very confused, please, the value range of (1) 3x + 2Y = P + 1, (2) 4x + 3Y = P-1, Y > x, P
①3x+2y=p+1
②4x+3y=p-1
①×7-②×5
21x+14y-20x-15y=7p+7-5p+5
x-y=2p+12
y>x
So X-Y
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