The open circuit voltage of an active linear two port network is 20 v. if it is connected to a five ohm resistor, a two ampere current will be generated The open circuit voltage of an active linear two port network is 20 v. if it is connected to a five ohm resistor, a two ampere current will be generated. The Thevenin equivalent circuit of the two port network can be obtained!

The open circuit voltage of an active linear two port network is 20 v. if it is connected to a five ohm resistor, a two ampere current will be generated The open circuit voltage of an active linear two port network is 20 v. if it is connected to a five ohm resistor, a two ampere current will be generated. The Thevenin equivalent circuit of the two port network can be obtained!

When the open circuit voltage of the two port network is 20V, the equivalent electromotive force of Thevenin equivalent circuit is 20V, and the equivalent internal resistance is R0 = 20 △ 2-5 = 5 Ω

There is an active two terminal network with an open circuit voltage of 12 V and an equivalent resistance of 6 ohm. Please draw the equivalent circuit of Thevenin,
And the resistance obtains the maximum power, and the resistance value and power of the resistance are calculated

In Thevenin equivalent circuit, the supply voltage is 12V and the internal resistance is 6ohm
When the external resistance is equal to the internal resistance, the maximum power is obtained, that is, the resistance value is 6 Ω, and the power = I × I × r = 1 × 1 × 6 = 6W
(current I = 12 / (6 + 6) = 1)