Find the maximum power of load resistor RL in the circuit below

As shown in the figure, the equivalent potential UAB, internal resistance Rab and RL = Rab of the network are obtained by using Thevenin's theorem. When UAB = 8 + 4 * 2 = 16 V & nbsp; & nbsp;; open circuit, I = 0, 4I = 0. Short circuit of a and B: (4 * ISC - 8) / 2 = 4 - ISC & nbsp; & nbsp; & nbsp

As shown in the figure, the circuit obtains the maximum power when calculating the value of load ZL, and what is the maximum power plmax?

Find Thevenin equivalent circuit, in the use of conjugate matching conditions
Actually, I don't want to do it

9. The circuit is shown in Figure 3. Try to find: (1) when the load impedance ZL is, the maximum power can be obtained? (2) what is the maximum power?

Because it is a constant current source, when parallel resonance, the impedance of the load part is the largest, and the power is also the largest, that is, ZL = - J4
The maximum power is I ^ 2 * r = 2W

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