Two light bulbs, one switch, one power wire, several switches are closed, only one light bulb is on, switch off, two light bulbs are on, how to draw the circuit diagram

Two light bulbs, one switch, one power wire, several switches are closed, only one light bulb is on, switch off, two light bulbs are on, how to draw the circuit diagram


Two bulbs in series, and then let the switch and one of the bulbs in parallel



There are three small light bulbs, dry battery, switch and wire. How to make three light bulbs shine at the same time? Draw the circuit diagram


1. The three bulbs are exactly the same --- --- lamp --- lamp -------- power supply -------- lamp --------. Lamp -------- lamp -------- power supply -------- 2. The three bulbs are totally different



Two bulbs L1 and L2 marked with "6V 3W" and "3V 3W" respectively. When they are connected in series, the maximum power that the circuit is allowed to reach is_____ W.
When they are connected in parallel, the maximum power that the circuit is allowed to reach is_____ W.


Yes, their resistances are r = u ^ 2 / P
That is, R1 = 12
R2=3
Seek the current again
I=P/U
5 and 1
If the series connection does not burn the bulb, the current should be 0.5
Therefore, the total yield P = I ^ 2 * (R1 + R2) = 3.75w
In parallel connection, the voltage should be calculated according to the minimum value of 3V
P=P1+P2=U^2/R1+U^2/R2=3.75W
In fact, the analysis of waxan people is correct



Two small bulbs marked with "3V 3W" and "6V 3W" are connected in series in the circuit. If one of the lamps works normally, the power supply voltage is (emergency)


I=3/3=1 R=3/1=3
I=3/6=0.5 R=6/0.5=12
"6V 3W" small bulb works normally
Supply voltage U = 0.5 * (3 + 12) = 7.5