A small bulb marked with "24 V 12 W" and a constant value resistor R are connected in series to the 36 V power supply, and the bulb will light normally ① At this time, what is the resistance R2 of the lamp? ② the size of R? ③ the electric energy consumed by the bulb in 1H? ④ the electric energy consumed by the lamp in 1H? ⑤ the electric power consumed by R (please write the answer process and description)

A small bulb marked with "24 V 12 W" and a constant value resistor R are connected in series to the 36 V power supply, and the bulb will light normally ① At this time, what is the resistance R2 of the lamp? ② the size of R? ③ the electric energy consumed by the bulb in 1H? ④ the electric energy consumed by the lamp in 1H? ⑤ the electric power consumed by R (please write the answer process and description)

1. Because the bulb lights normally, RL = UL & # 178 / / P = (24 V) & # 178 / / 12W = 48 Ω 2. The constant resistance is connected in series with L, so ur = u-ul = 36v-24 v = 12vi = PL / UL 12W / 24 V = 0.5ar = ur / I = 12V / 0.5A = 24 Ω 3. W = pl · t = 12W × 3600s = 43200j4. Q = it = 0.5A × 3600s = 1800c5. PR = ur · I = 1

There is a small light bulb marked with "6V 3W". If it is connected to 9V power supply, in order to make it shine normally, it should be connected in series with a resistance of______ The constant resistance of Ω

When the bulb is normally emitting, the voltage UL = 6V, the power pl = 3W, the current I = IL = plul = 3w6v = 0.5A, the voltage ur = u-ul = 9v-6v = 3V, r = URI = 3v0.5a = 6 Ω

A small "6V, 3W" light bulb, connected to a 24 V power supply, should be connected in series with an 18 V, 3W light bulb for normal lighting, right?

If r = 12 ohm is obtained from P = u / R, a 36 ohm resistor should be connected in series to the 24 V power supply
18V 3W resistance is 18 * 18 / 3 = 108 ohm, more than 36 ohm
So the light bulb doesn't work