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What is the meaning of this formula in the electric energy meter w = n / revolution, w refers to () n () revolution refers to (), by the way, what is electric work? It's better to understand it by yourself
N is the number of revolutions, the correct formula is n / 3600000j, is to calculate the kilowatt hour (kW. H), 1 kilowatt hour = 1000 watts * 3600 seconds = 3600000 joules. The electric work is the work done by the current (see science textbook in grade 3), the calculation formula is w = Pt, w = uitw = I & sup2; RT
W=(U²t)/R
On the third floor, don't make a fuss if you don't know
On the revolution of physical watt hour meter
Xiaoming's home appliance meter is marked with the words of 220 V 10 (20) a, 50 Hz, 1500 R / kW. H. first question: when there is a refrigerator in the house working normally, he measured that the meter turns three times a minute and asked how many joules the refrigerator consumes during this period of time. Second question: when the refrigerator and hot water kettle are working normally, he measured that the meter turns 33 times a minute, How many watts is the electric power of the kettle at this time? The third question: if the kettle is used to heat 1kg of water from 20 ℃ to boiling, what is the time required? {the pressure is the standard atmospheric pressure, regardless of the heat loss, the specific heat capacity of water is 4.2 × 10J}
1. The energy consumed by refrigerator w = revolutions n / parameter of energy meter n = 3 revolutions / (1500 revolutions / kWh) = 0.002 kwh = 2 × 10 to the negative third power, kwh = 2 × 10 to the negative third power, 3.6 × 10 to the sixth power, j = 7200 J 2. When refrigerator and kettle work normally, the turntable of energy meter turns 33 times a minute. When refrigerator works normally alone, the turntable of energy meter turns 3 times a minute, The electric energy consumed by the kettle is w = revolutions n / the parameter of the meter is n = 30 revolutions / (1500 revolutions / kWh) = 0.02kwh = the minus second power of 2 × 10 kwh = the minus second power of 2 × 10 kwh = the sixth power of 3.6 × 10 J = 72000j, the electric power of the kettle is p = w / T = 72000j / 60s = 1200w3, the heat absorbed by water is q = cm (t-to) = 4200j / kg ℃× 1kg × (100 ℃ - 20 ℃) = 336000j The electric energy consumed by the electric kettle w = Pt, without considering the heat loss, q = W. the power on time t = w / P = 336000j / 1200W = 280s
How to use the electric energy meter and stopwatch to calculate the electric power
p=3600n/tc
n. The number of laps you take when you measure,
T. You have time
C. Meter constant
Principle of measuring electric power with electric energy meter and stopwatch
P＝W／t
The electric energy W is measured by the electric energy meter and the time t is measured by the stopwatch
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