How many Ω is the resistance of the filament when the flashlight bulb is emitting? How many Ω is the resistance of the copper wire used in the experiment, so it can be ignored

How many Ω is the resistance of the filament when the flashlight bulb is emitting? How many Ω is the resistance of the copper wire used in the experiment, so it can be ignored


The resistance of the small bulb in the flashlight is about 10 ohm
The resistance of copper conductor is related to its sectional area and length
R=ρL/S
The resistivity of copper is ρ = 0.0185 Ω· mm ^ 2 / m. for a copper conductor with a length of 100 mm and a diameter of 1 mm, the resistance is:
R=0.0185X0.1/(3.14x0.5^2)≈0.002(Ω)



The filament resistance of a festival lantern is 30 Ω, and the current is 0.2 a when it works normally. How much voltage should be applied at both ends of the lantern?


Probably choose 8-9v voltage, according to the conditions you give, the theoretical algorithm is 6V, but it is not the case in reality, because you may measure the filament resistance at room temperature, and the filament resistance will become much larger in actual work, which is also the parameter that the manufacturer will not give you. To know the voltage at both ends of the lamp, you can use one can



In a series circuit, the distribution of voltage is proportional to the resistance


This is Ohm's law. In a circuit, the resistance is constant. The higher the voltage, the greater the current. The current is proportional to the voltage
In the circuit, the current is constant, the greater the resistance, the higher the voltage. At this time, the resistance is proportional to the voltage



How to distribute the voltage of series circuit according to resistance


1. The sum of the voltages of each part of the series circuit is equal to the total voltage
2. The voltage ratio of each series part in the series circuit is equal to the resistance ratio
That is to say, the voltage of each part is proportional to the resistance of each part