The voltage at both ends of the power supply is 6V, R1 and R2 are constant resistance. After closing switch s, the indication of ammeter is 0.2A, and that of voltmeter is 4V What are the resistance values of R1 and R2? Write out the process, too```
Which resistance is the voltmeter connected to?
If U2 = 4V, then:
U1=U-U2=6-4=2V
R1 = U1 / I = 2 / 0.2 = 10 (Euro)
R2 = U2 / I = 4 / 0.2 = 20 (Euro)
The current number is 0.6A, the resistance value of resistance R2 is 20 Ω, the current through R2 is 0.4A, and the power supply voltage is calculated
U=IR=20*0.4=8V
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