Three phase load star connection, three-phase symmetrical load, each phase resistance R = 24 Ω, inductance XL = 32 Ω, access line voltage 380V three-phase power supply, calculate the phase current

Three phase load star connection, three-phase symmetrical load, each phase resistance R = 24 Ω, inductance XL = 32 Ω, access line voltage 380V three-phase power supply, calculate the phase current

R=24Ω, XL=32Ω Z=(R*R+X*X)^0.5=40Ω
Phase voltage U = 380 / √ 3 = 220 V phase current I = u / z = 220 / 40 = 5.5A

How to calculate the three-phase power of pure resistance load in star connection and triangle connection? External three-phase 380V power supply, each phase resistance is r, is my algorithm right?
For star connection, P = 3U (phase voltage) I (phase current) = 3 × 220 × (220 / R)
For triangle connection, P = 3U (phase voltage) I (phase current) = 3 × 380 × (380 / R),
Is the phase current I 380 / R in triangle connection correct?

Your calculation is correct on the premise that the three-phase power supply is a three-phase symmetrical power supply with 380V line voltage. It is completely correct on this premise, because the phase voltage and phase current of pure resistance load are in phase, and there is no phase difference. I and u in I = u / R correspond to the same R, which is correct

A three-phase asynchronous motor is Y-connected and connected to a three-phase symmetrical power supply with line voltage of 380V. The motor operates under rated voltage. Its equivalent resistance of each phase is 8 Ω and equivalent reactance is 6 Ω. The current, power factor, active power and 1-hour power consumption of the motor are tested

Known: y connected, line voltage U1 = 380V, so phase voltage U2 = 220V
R = 8 Ω X = 6 Ω Z = (R * R + X * X)^0.5 = 10 Ω
Current: I = U2 / z = 220 / 10 = 22 A
Power factor: ψ = R / z = 8 / 10 = 0.8
Active power: P = 3 * I * I * r = 3 * 22 * 22 * 8 = 11616 w = 11.616 kw
1 hour power consumption: q = P * t = 11.616 * 1 = 11.616 kWh (KWH)

Given a three-phase symmetrical load, the resistance of each phase load r = 6, inductive reactance XL = 8, and the line voltage of the power supply is 380V, the respective values of the triangle connection and star connection of the load are calculated
Each power should be calculated

2, first calculate the angular phase current I = 380 / 10 = 38a, line current = 3 times the root phase current = 1.732 x 38 = 65.8a, power P = 1.732 x 0.38 x 65.8 = 43.3kw, 3, star phase current I = 220 / 10 = 2