How to transform (x + 2) ^ 2 + (Y-5) ^ 2 = 16 to polar coordinate equation? If it's convenient, please list the equation of P for me,

Let x = RCOs α, y = rsin α, α ∈ (0,2 π)
The polar coordinate equation can be obtained by substituting the original equation
（rcosα＋2）^2＋（rsinα－5）^2=16
It is concluded that R ^ 2 -- 10rsin α + 4rcos α + 13 = 0

Transformation of polar coordinate equation into ordinary equation
ρ = - 10cos θ PS: how can we use x = cos θ * ρ y = ρ * sin θ to replace sin θ / cos θ separated from ρ?

ρ=-10cosθ
Multiply both sides by ρ and replace them

The position of ABC three numbers on the number axis is shown in the figure. Try to simplify the formula
Formula: a | a | + B | + C ||
Number axis__ c_ 0_ a b______________

A | a | + B | + C ||
=1+1-1
=1

The corresponding points of rational number ABC on the numeration axis are shown in the figure
The corresponding points of rational numbers a, B and C on the number axis are shown in the figure, where o is the origin. Simplify | a | - | a + B | + | C-A | + | B-C|
Picture:
------------------------------------------→
c d O a

It can be seen from the figure that a > 0 > b > C, | C | > | B | > A, a + B < 0, | a + B | = - (a + b) | C - a | = a - C | B - C | = B - C | - a + B | + | C-A | + | B-C | = a - [- (a + b)] + a - C + B - C = a + A + B + a - C + B - C = 3A + 2B -

If a and B are known (2a is larger than B), draw with a ruler and a compass, and draw the line AB so that ab = 2a-b

Given a, B (2a & gt; b), draw with a ruler and a compass, and draw the line AB so that ab = 2a-b
1. Do ray am, intercept AC = 2A on am
2. Intercept CB = B on CA
Then AB = 2a-b

If line segments a and B are known (a > b), draw with ruler and Compass: (1) draw line segment AB so that ab = 2a-2b;
(2) Draw the line CD so that CD = 2 (a-b)
(3) What is the size relationship between line AB and CD

As shown in the figure, given the line a, B, and a & gt; B, use a ruler and a compass to make a line AB, so that the line B is equal to 2a-b

Take point o as the center of the circle and a as the radius to draw a circle. Take any point a on the circle, pass through the center O, connect AO and intersect circle C, so AC = 2A
Draw a circle with point C as the center and B as the radius, intersecting AC with B

How to make a vertical bisector of a line segment with a ruler and a compass, and explain the reason
I mean, what is the principle of this method

Method 1
1. Take the midpoint of the line segment
2. Take the two ends of the line segment as the center of the circle, and draw an arc with a radius greater than half the length of the line segment
3. Connect the two intersections
Principle: bisect the bottom of an isosceles triangle vertically
Method 2
1. Take the two ends of the line segment as the center of the circle, and draw the arc with the radius greater than half the length of the line segment to get two intersections. Principle: the radius of the circle is equal everywhere
2. Connect the two intersections. Principle: two points form a line

So far, we have learned the ruler and compass drawing mainly as follows: 1. Make a line segment equal to a known line segment; 2. Make a known angle__________ .

So far, we have learned the ruler and compass drawing mainly as follows: 1. Make a line segment equal to a known line segment; 2. Make bisector of a known angle

Given the line segment AB, how to make a line segment equal to the line segment AB with a ruler and a compass!

First place the supporting point of the compass on a, and then place the other foot on B, so that the distance between the two feet of the compass is the distance of line ab
On paper, use a compass to dot two points, so that the distance between the two points is the distance of line ab
Then connect the two points with a ruler

How to transform (x + 2) ^ 2 + (Y-5) ^ 2 = 16 to polar coordinate equation? If it's convenient, please list the equation of P for me,