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The rated power of a car with a mass of 10t is 60kW, and the maximum speed of driving on the horizontal road is 15m / s. if the motion resistance of the car remains unchanged, the motion resistance of the car is______ N. Acceleration at rated power when vehicle speed is 10m / S______ m/s2．
When the car runs on the horizontal road with rated power and reaches the maximum speed, the formula of power is p = FV, f = PV = 60 × 10315n = 4 × 103n & nbsp; at this time, the resistance is equal to the traction force, that is, 4000N. When the car runs on the horizontal road with rated power and the speed is 10m / s, it can be obtained from Newton's second law: PV − f = ma & nbsp; A = PV − FM = 60 × 10310 − 400010 × 103m / S2 = 0.2m/s2, so the answer is: 4000; 0.2
The rated power of the automobile engine is 60kW. When the rated power of the automobile runs at a constant speed on a straight road v = 20m / s, what is the resistance of the automobile at this speed?
The magnitude of resistance is: 60000 / 20 = 3000n
The rated power of a car with a mass of 10t is 60kW, and the maximum speed of driving on the horizontal road is 15m / s. if the motion resistance of the car remains unchanged, the motion resistance of the car is______ N. Acceleration at rated power when vehicle speed is 10m / S______ m/s2．
When the car runs on the horizontal road with rated power and reaches the maximum speed, the formula of power is p = FV, f = PV = 60 × 10315n = 4 × 103n & nbsp; at this time, the resistance is equal to the traction force, that is, 4000N. When the car runs on the horizontal road with rated power and the speed is 10m / s, it can be obtained from Newton's second law: PV − f
The mass of the car is 5T, the rated power of the engine is 60kW, and the resistance on the road is 2000N
The mass of a certain type of vehicle is 5T, the rated power of the engine is 60kW, and the resistance is 2000N when driving on the horizontal road. If the vehicle starts to move in a straight line with a uniform acceleration of 0.2m/s2 from a stationary state, then:
(1) The time to maintain this acceleration;
(2) The instantaneous power of the vehicle at the speed of 10m / S;
(3) If the car reaches its maximum speed and the resistance suddenly doubles, what will it do?
According to 5T = 5000kg, 60kW = 60000w1, t = 100sp = w / T, w = FS, so p = f * V and f-f = m * a = 5000 * 0.2 = 1000N, so f = 1000 + 2000 = 3000np = f * V = 3000 * a * t = 3000 * 0.2 * t, t = 100s2. When the speed is 10m / s, P = f * V = 3000 * 10 = 30000w
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