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The school plans to use 56 tons of coal in December, 16 tons less than the plan?
56 × (1-16) = 56 × 56 = 2536 (tons) a: the actual coal consumption is 2536 tons
Five twelfth of a pile of sand was used in the first time, one sixth of a ton was used in the second time, and two ninth of a ton was left. How many tons of sand was there
Seeking arithmetic solution
(2/9+1/6)÷(1-5/12)
=7/18÷7/12
=12/18
=2/3
This pile of sand used to be two thirds of a ton
The school's coal burning in April is one ninth less than that in March, one sixth more than that in April, and one sixth more than that in April
1/6÷1/9-1/6=3/2-1/6=9/6-1/6=4/3t
There is a pile of coal, sold 1000 kg, is exactly one sixth of this pile of coal, how many tons of this pile of coal
If the problem, please use the formula to solve, thank you
1000 △ 1 / 6 = 6000 kg
1000 kg = 1 ton
6000 kg = 6 tons
This pile of coal is six tons
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