There are two baskets of apples. The weight of the first basket is 10 parts of the second basket. If you take 10 kg from the second basket and put it into the first basket, the two baskets are equal?

There are two baskets of apples. The weight of the first basket is 10 parts of the second basket. If you take 10 kg from the second basket and put it into the first basket, the two baskets are equal?


10+9/10*x=x-10
X = 200 kg
Total weight of two baskets 200 + 200% 9 / 10 = 380



A and B have two baskets of apples. The number of a basket is three times that of B. if 10 apples are taken out of a basket and put into B basket, the number of two baskets is equal. How many apples are there
(column equation)


Suppose there were x baskets in basket B and 3x baskets in basket a
3X-10=X+10
2X=20
X=10
A basket 10 * 3 = 30 (pieces)



The number of apples in basket a is 2.4 times of that in basket B. If 35 apples are taken out of basket a and put into basket B, the number of apples in the two baskets is equal. How many apples are there in the two baskets?


If there are x apples in basket B, then there are 2.4x apples in basket A. according to the meaning of the question, we can get the equation: 2.4x-x = 35 × 2, & nbsp; 1.4x = 70, & nbsp; & nbsp; & nbsp; & nbsp; X = 50, 50 × 2.4 = 120. A: there are 120 apples in basket a and 50 apples in basket B



There are two baskets of apples. The number of apples in basket B is 2 / 5 of that in basket A. after 10 apples are taken out of basket a and put into basket B, the number of apples in basket B is 3 / 4 of that in basket A. how many are there in total?


It turns out that a accounts for 1 (2 / 5 + 1) = 5 / 7 of the total
Now a is 1 (1 + 3 / 4) = 4 / 7
So a total of 10 (5 / 7-4 / 7) = 70