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A and B trains leave from both places at the same time. Train a travels 50 kilometers per hour and train B 60 kilometers per hour. When the two trains meet, train a travels 300 kilometers, How many kilometers are there between the two places
300 △ 50 × (50 + 60) = 660km
The two trains run from two cities at the same time. Car a runs 50 kilometers per hour, and car B runs 60 kilometers per hour. The two trains meet 30 kilometers away from the destination to find the distance between the two cities
Is that the original title
City a city B
|---------------------------|
A → 50km / h, 60km / h ← B
What do you call the end point? 30 kilometers?
The title is not clear`
(30 + 30) / (60-50) = 6 (hours)
50 * 6 + 60 * 6 = 660 (km)
Train a and train B depart from the two cities at the same time. Train a travels 60 kilometers per hour, while train B travels 50 kilometers per hour. When the two trains meet, train a just travels 300 kilometers. How many kilometers are there between the two places?
300 divided by 60 equals 5, which means that Party A walked for 5 hours when Party A and Party B met. Because they started at the same time, Party B also walked for 5 hours, so 5 * 50 = 250 is the distance that Party B walked, so 300 + 250 = 550 is the distance between the two places
The speed of a car is one third slower than that of a train, that is to say, the speed of a train is faster than that of a car
Suppose the speed of the train is 1, then the car is 1 / 3 slower than the train, that is 1-1 / 3 = 2 / 3,
Now the car is 2 / 3, the train is 1, the train is faster than the car, is (1-2 / 3) △ 2 / 3 = 1 / 2 is the answer to this question
A is a fraction faster (slower) than B is (a-b) △ B
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