Given the angle a = 72 degrees 36 ', then the complement of the remainder of angle a is () degrees Look at the unit Is it 162.6 degrees in the end?

Given the angle a = 72 degrees 36 ', then the complement of the remainder of angle a is () degrees Look at the unit Is it 162.6 degrees in the end?

It should be 162 degrees 36

If ∠β = 41 ° 25'35 "is known, find the residual angle and complementary angle of ∠β

Residual angle: 90 ° - 41 ° 25 ′ 35 ″ = 48 ° 34 ′ 25 ″
Complementary angle: 48 ° 34 ′ 25 ″ + 90 ° = 138 ° 34 ′ 25 ″

Given ∠α = 36 ° 26 ', find its complementary angle and complementary angle
And find out how much bigger the complement angle is than the remainder angle

Residual angle = 90 & # 186; - 36 & # 186; 26 '= 53 & # 186; 34'
Complement = 180 & # 186; - 36 & # 186; 26 '= 143 & # 186; 34'
The complement angle is larger than the remainder angle: 143-53; 34 '= 90;