Two conclusions are given: 1. The sum of the last two digits of odd perfect square is odd; 2. The sum of the last two digits of even perfect square is even

1. The sum of the last two digits of odd perfect square is odd;
One digit must be odd, ten digit must be even
therefore
Sum is odd, right
2. The sum of the last two digits of even perfect square is even
This error, such as 4 & # 178; = 16, and is odd

Hehe, I forgot how to find it: X * 2-12x-2010 = 0, one variable quadratic equation, where x * 2 is the square of X

The above formula is changed to (X-6) ^ 2 = 2046
We get x = 6 + root 2046
Or x = 6-radical 2046

Is the square of x minus X / 1 a quadratic equation of one variable? I remember the teacher said that x can't be the denominator

You see how the book defines the quadratic equation of one variable
An integral equation with only one unknown and the highest degree of the unknown is quadratic is called a quadratic equation with one variable
Pay attention to the four words "formal equation" in the definition, which means that the unary quadratic equation does not include the fractional equation, so the unknowns cannot appear on the denominator. For example, X-1 / x = 0, although the denominator can be reduced to x ^ 2-1 = 0, X-1 / x = 0 is a fractional equation, not a unary quadratic equation

Given that the sum of squares of three consecutive even numbers is 251, what is the product of these three numbers

(x-2)^2+x^2+(x+2)^2=251
3x^+8+251
x^2=81
X = 9 or - 9
Therefore, the three numbers are not continuous even numbers, which is inconsistent with the meaning of the title

Verification: the product of the number of one digit and ten digit of any perfect square B must be even

The last digit of a complete square number can only be 0, 1, 4, 5, 6, 9. The odd number of the square number is odd, and the ten digit number is even. (thus the product of the two is even). If the safe square number is the square of an even number, it is not necessary to prove? O (∩)_ ∩) O ~ when the perfect square is the square of an odd number

The sum of five consecutive even numbers is a complete square number, and the sum of three even numbers in the middle is a cubic number
emergency

Let the even number in the middle be 2n, the sum of five consecutive even numbers be 10N, and the sum of three even numbers in the middle be 6N, then 10N = k ^ 2 and 6N = m ^ 310n = k ^ 2. Obviously, there must be a factor 10 in N; 6N = m ^ 3 obviously, there must be a factor 36 in N. suppose that n = 360 does not satisfy 6N = m ^ 3 expansion of 100 times (integral square), n = 36000

Try to explain: the product of two continuous odd numbers plus 1 must be the square of an even number

Let two continuous odd numbers be 2N-1, 2n + 1, then (2n-1) (2n + 1) + 1 = (2n) 2-1 + 1 = (2n) 2, the result is true

Try to explain: the product of two continuous odd numbers plus 1 must be the square of an even number

Let two continuous odd numbers be 2N-1, 2n + 1, then (2n-1) (2n + 1) + 1 = (2n) 2-1 + 1 = (2n) 2, the result is true

It is proved that the product of odd numbers before 50 and even numbers after 50 is the complete square of an integer
Please see clearly, it's product, product! All products are product. Please improve your Chinese~`~

There are 25 even numbers after 50, which can be expressed as the product of several 2 and all odd numbers before 50 (except 1, of course, there are 24). The details are as follows: 64:1; 32:3; 16:5; 8:7, 9, 11; 4:13, 15, 17, 19, 21, 23, 25; 2:27, 29, 31

Two conclusions are given: 1. The sum of the last two digits of odd perfect square is odd; 2. The sum of the last two digits of even perfect square is even