Given the function y = (M-3) x ^ (m ^ 2-10), when what is the value of M, it is an inverse scale function? In which quadrant is his image located

Given the function y = (M-3) x ^ (m ^ 2-10), when what is the value of M, it is an inverse scale function? In which quadrant is his image located

The degree of the inverse scale function is - 1
m²-10=-1
m²=9
m=±3
The coefficient is not equal to 0
m-3≠0
m≠3
So m = - 3
y=-6/x
So in the second and fourth quadrants

It is known that the image of inverse scale function passes through point a (- 3,2). Which quadrant is the image of this function located in? How does y change with the increase of X? Is B (3,4) C (3, - 2) d (1.5, - 4) on the image of this function

If the image of the inverse scale function passes through point a (- 3,2), the analytic expression of the function is y = - 6 / X,
In each quadrant, y increases with the increase of X
C. D is on the function image, B is not

Given the inverse scale function y = K-2 / x, its image is in the first and third quadrants, the value range of K is obtained

If the image is in the first and third quadrants, the molecules are positive
k-2>0
So k > 2

In which quadrant is the image with inverse scale function y = - 6 / X located

In which quadrant is the image with inverse scale function y = - 6 / X located
When k > 0, the image with inverse scale function y = K / X is in one or three quadrants