Find the analytic expression of quadratic function satisfying the following conditions (1) The abscissa of the intersection of the parabola and the X axis is - 5 and 1, and the intersection of the parabola and the Y axis is at the point (0,5) (2) There is only one common point (2,0) between the parabola and the x-axis, and it intersects the y-axis at the point (0,2) (3) When x = 2, the minimum value of y = - 4, and the image passes through the origin Give points for answers before 9 o'clock

Find the analytic expression of quadratic function satisfying the following conditions (1) The abscissa of the intersection of the parabola and the X axis is - 5 and 1, and the intersection of the parabola and the Y axis is at the point (0,5) (2) There is only one common point (2,0) between the parabola and the x-axis, and it intersects the y-axis at the point (0,2) (3) When x = 2, the minimum value of y = - 4, and the image passes through the origin Give points for answers before 9 o'clock

Let a parabola be y = a (x + 5) (x-1) and intersect with y axis at point (0,5), that is, 5 = a (5) * - 1, that is, a = - 1, that is, y = - (x + 5) (x-1) = - x & # 178; - 4x + 52 parabola and X axis have only one common point (2,0), then y = a (X-2) &# 178; and passing through point (0,2), that is, 2 = a * (- 2) &# 178; that is, a = 1 / 2, that is, y = 1 / 2

According to the following conditions, the analytic expression of quadratic function is obtained
(1) The image passes through points (1, - 2), (0, - 3), (- 1, - 6);
(2) When x = 3, the function has a minimum value of 5 and passes through points (1,11);
(3) The graph of the function intersects the x-axis at two points (1-radical 2,0) and (1 + radical 2,0) and intersects the y-axis at (0, - 2)
I'm sorry, but I'm not

1. Let y = ax ^ 2 + BX + Ca + B + C = - 2, C = - 3, A-B + C = - 6, the solution is a = - 1, B = 2, C = - 3 ∧ y = - x ^ 2 + 2x-3.2. Let y = a (x-3) ^ 2 + 5 ∫ f (1) = 11, ∧ 4A + 5 = 11, a = 3 / 2 ∧ y = 3 / 2 (x-3) ^ 2 + 53. Let y = a (x-1 + radical 2) * (x-1 - radical 2) ∫ f (0) = 2 ∧ a = - 2; 2; y = - 2 (x-1 + radical 2) * (x-1 - radical 2) ∧

According to the following conditions, find the analytic expression of quadratic function, image passing through point (1,6) (- 1,0) (2,12)

Let the analytic expression of quadratic function be y = ax & # 178; + BX + C
∵ quadratic function, image passing point (1,6) (- 1,0) (2,12)
∴6=a+b+c 3/2-B+3/2
0=a-b+c
12=4a+2b+c
The solution is a = 3 / 2
b=3
c=3/2
The analytic formula of quadratic function is y = 3x & # / 2 + 3x + 3 / 2