In the triangle ABC, angle ACB = 90 degrees, angle B = 35 degrees, CD is the height of hypotenuse ab. find the best BCD and the degree of angle A

In the triangle ABC, angle ACB = 90 degrees, angle B = 35 degrees, CD is the height of hypotenuse ab. find the best BCD and the degree of angle A

In △ ABC, CD is the high on the hypotenuse ab,
In △ CDB, ∠ BCD = 180-90-35 = 55 °
In △ ABC, a = 180-90-35 = 55 degree
∴∠A=∠BCD=55°

As shown in the figure, in △ ABC, the angle ACB = 90 °, a = 30 °, CD ⊥ AB at point D, ab = 4cm, find the length of BC, ad, BD and the degree of ⊥ BCD

Because ∠ a = 30 degree
Using trigonometric function to get
BC side = 1 / 2Ab side = 2cm
And because ∠ C is divided into two parts by CD side, which are ∠ BCD and ∠ ACD
Then, we use ∠ a to get ∠ BCD = 30 °
AD=1cm,BD=3cm

In RT triangle ABC, CD is the height of hypotenuse ab,

As shown in the figure, in the RT triangle ABC, the angle D is the height of the edge AB, and the angle BCD = 35 degrees. Find the degree of angle A and angle EBC

I don't know where e is. The problem is to find the degree of angle A and angle ABC
Because the triangle ABC is a right triangle, the angle c = 90 degrees, and because the angle BCD = 35 degrees and D is the height of AB, the angle ABC = 180-35-90 = 55 degrees
So angle a = 90 degrees - 55 degrees = 35 degrees
I don't know if it's right. Because I didn't see the picture. I can only count and draw by myself. I hope it's right