If the perimeter of △ ABC is 12cm and the area of △ DEF is 8cm, then the perimeter of △ DEF is ---. △ ABC If the perimeter of △ ABC is 12cm and the area of △ DEF is 8cm, then the perimeter of △ DEF is --------. The perimeter of △ ABC is ---.

The perimeter of △ DEF is 12 cm
The area of ABC is 8cm

If the similarity ratio of △ ABC and △ DEF is 3:4, the perimeter ratio of △ ABC and △ DEF is 0______ ．

∵ ABC ∵ def, and the similarity ratio is 3:4, and ∵ the perimeter ratio of similar triangles is equal to the similarity ratio, ∵ their perimeter ratio is 3:4

RELATED INFORMATIONS

1. If △ ABC is similar to △ def, the similarity ratio is 3:2, if their perimeter difference is 40 cm, then the perimeter of △ DEF is?
2. It is known that the lengths of three sides of △ ABC are a, B, C, and the perimeter is 6, and a ^ 2 + B ^ 2 + C ^ 2 = AB + BC + Ca, then the lengths of three sides of △ ABC are?
3. Given that a, B and C are the three sides of △ ABC, and a + B + C = 60cm, a: B: C = 3:4:5, the area of △ ABC is obtained
4. At RT △ ABC, ∠ C = 90 °, girth 60cm, two right angle sides, BC: AC = 5:12, find the value of s △ ABC Pythagorean theorem in Mathematics
5. It is known that the perimeter of △ ABC is 18cm, and a + B = 2c, a − B = C2. Find the length of a, B, C on three sides
6. As shown in the figure, △ ABC midpoint D is on BC, and after rotating around point a, △ ABC coincides with △ ace. If ∠ ECB = 100 °, then the rotation angle is?
7. Given that the lengths of each side of a triangle are 8 cm, 10 cm and 12 cm respectively, the perimeter of the triangle with the midpoint of each side as the vertex is 0______ cm．
8. If the lengths of the three median lines of a triangle are 3, 4 and 5, then the circumference of the triangle is 3______ ．
9. It is known that the ratio of three median lines of triangle is 3:5:6, and the perimeter of triangle is 112cm
10. As shown in the figure, the perimeter of the first triangle is known to be 1, its three median lines form the second triangle, and the three median lines of the second triangle form the third triangle, and so on. The perimeter of the first triangle is 1________ .
11. There are three schools a, B, Let three schools a, B and C be located at the three vertices of an equilateral triangle. In the Internet age, to set up communication cables between the three schools, Xiao Zhang designed three connection schemes, as shown in the figure, scheme a AB + BC; scheme B AD + BC {D is the midpoint of BC}; scheme C Ao + Bo + CO (o is the intersection of the three heights of the triangle). Please help to calculate which of the following schemes has the shortest route
12. Given the equation x * - 5x - 1 = 0 about X, find the value of (1) x + 1 / X
13. 】Given that x is any number except 2, x ^ 2 + 2x + 1 / (X-2) ^ 3 = A / X-2 + B / (X-2) ^ 2 + C / (X-2) ^ 3, find the value of a, B, C Given that x is any number except 2, x ^ 2 + 2x + 1 / (X-2) ^ 3 = A / X-2 + B / (X-2) ^ 2 + C / (X-2) ^ 3, find the value of a, B, C
14. It involves solving triangles and vectors In △ ABC, the opposite sides of ∠ a, B, C are a, B, C, vector M = (a ^ 2, B ^ 2), vector n = (Tana, tanb), and vector M / / vector n. then what is the shape of △ ABC?
15. In the triangle ABC, the opposite sides of a, B, C are a, B, C, a = π / 6, (1 + radical 3) C = 2B, find C I'll give you five points when I finish
16. The known vectors AB = (6,1), BC = (x, y), CD = (- 2, - 3) (1) If BC is parallel to Da and AC is perpendicular to BD, then x and y are obtained (2) Find the area of quadrilateral ABCD All AB, BC. Above are vectors
17. Vector representation of triangle interior If O is a triangle ABC, ab = C, AC = B, BC = a, prove a * [0A] + b * [ob] + C * [OC] = [0] ([OA] denotes vector OA) I asked why
18. On vectors It is known that AC vector is the sum of AB vector and Ad vector, AC vector = a, BD vector = B, AB vector and Ad vector are represented by a respectively
19. 1. Given the points a (2,3), B (5,4) and C (7,10), if the vector AP = AB + λ AC (λ∈ R), what is the value of λ, the point P is in the third quadrant? 2. (1) it is proved that three non parallel vectors a, B and C can form a triangle (the starting point of each vector coincides with the end point of one of the other two vectors) if and only if a + B + C = 0 (2) It is proved that three midline vectors of a triangle can form a triangle (3) In △ ABC, e and F are points on AC and AB, respectively. Be and CF intersect at point g. given CE = 1 / 3CA, BF = 2 / 3ba, calculate the constants λ and μ, such that GE = λ be, GF = μ CF & # 61549;, # 61472 3. As shown in figure 5-3-19, e and F are the edges of ABCD, ad and the midpoint of CD, and be, BF and diagonal AC intersect at points R and t respectively Verification: ar = RT = TC 4. Try to prove: the necessary and sufficient condition for the end points a, B and C of three vectors a, B and C with the origin as the starting point to be on the same straight line is that C = α a + β B (α, β ∈ R, and α + β = 1) Before 6 am on the 21st, don't look down on us
20. Given the direction vector a of the line L = (1,3), the direction vector of the line L 'is b = (- 1, K). If the line L' passes through the point (0,5) and l ⊥ L ', then what is the equation of the line L' Above is the original title The answer given in the book is ∵a=(1,3) ,b=(-1,k), ∴a·b=-1+3k=0 And because the line L 'passes through the point (0,5) And l ⊥ L ', then the equation of L' is X-3Y+15=0 I don't think the K in B (1, K) should represent the slope? Here's what I did, Let the equation of line L 'be y-0 = K (X-5) That is, the point oblique formula of the column. This should be OK. After multiplying it, it becomes Y = kx-5k, the slope of L 'should be the K I set! Then from the direction vector a + (1,3) of L, we know that the slope of l should be 3 The slope k of L 'should be - 1 / 3 Then we substitute y = kx-5k to get x + 3y-5 = 0 I love to go to the top, thank you very much!