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When studying the relationship between acceleration mass and resultant force It is said in the book that the car should move on the board with little friction. It is better to have no friction. If there is no friction, then when studying the relationship between acceleration and car mass, keep the tension unchanged. Why should the acceleration decrease when the mass increases? It should remain unchanged, because if there is no friction, there will be no friction coefficient, so the car mass has nothing to do with friction, No matter how big the mass is, the friction force is always 0. In this way, the pull force remains the same, so the acceleration of the car will remain the same Why does the teacher say that acceleration is inversely proportional to mass? If there is a little friction on the ground, that's true If there are two objects with different masses in the universe, their gravity and friction are ignored. If you push them with the same force, will they move in a straight line at the same speed?
It is an experimental fact that the acceleration decreases when the mass increases while the tension remains unchanged. It is also because there is no friction that we can deduce the conclusion that the acceleration is inversely proportional to the mass (a = f / M)
Vector coordinate formula, collinear, vertical, note that the coordinates
a(x1,y1,) b（x2,y2,)
Collinear: x1y2-x2y1 = 0
Vertical: x1x2 + y1y2 = 0
The vertical and parallel formula of two vectors
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