If Tan α = - α, the value of Tan (π - α) is equal to? Detailed process

If Tan α = - α, the value of Tan (π - α) is equal to? Detailed process

sin（π-α）=-sinα
cos(π-α）=-cosα
So tan (π - α) = Tan α = - α

Tan A is equal to 2.45, a is equal to how many degrees?

tan a=2.45
A = arc Tan 2.45 = 67.7965 degrees

In the triangle ABC, angle a - angle B = 15 degrees, angle c - angle B = 60 degrees, find the degree of each internal angle of the triangle!
How to make equations

A+B+C=180
A-B=15
C-B=60
Solve the equation by yourself

In triangle ABC, if angle a = 40 ° and angle B minus angle c = 60 °, what is the degree of angle c?

∵∠A＝40°
In the triangle ABC, a + B + C = 180 degree
∴∠B+∠C=180°-40°=140°①
∠B-∠C=60° ②
From ① - ②, we can get ∠ C = 40 °
A: the degree of ∠ C is 40 degrees

It is known that the degree ratio of the five inner angles of a Pentagon is only 2:3:4:5:6. The degree ratio of the largest inner angle and each outer angle of the Pentagon is only 2:3:4:5:6

In Shaozhu Ming Dynasty, the largest inner angle is 162, and the degree of each outer angle is only 17:14:11:8:5:2. The analysis is as follows: because the sum of inner angles of polygon = (number of sides - 2) * 180, the sum of inner angles of Pentagon = (5-2) * 180 = 540, the largest inner angle is 540 * 6 / (2 + 3 + 4 + 5 + 6) = 162, and the five inner angles are 54, 81108135162 (such as 540 * 2 / (...)

It is known that the ratio of the degree of the inner angle of the Pentagon is 4:4:5:5:6, and the ratio of the corresponding degree of each outer angle of the Pentagon is calculated

Let the minimum internal angle of a Pentagon be 4x
The sum of internal angles of Pentagon is 540 degrees
All
4x+4x+5x+5x+6x=540
24x=540
x=22.5
The five internal angles are
90,90,112.5,112.5,135
So the five outer corners are
90,90,67.5,67.5,45
The ratio of their outer angles is 4:4:3 "3:2

It is known that the ratio of the degrees of the five outer angles of a Pentagon is 4:3:2:2:1. Find the degrees of the five inner angles of the Pentagon

The sum of the exterior angles of the polygon is 360 degrees
4x+3x+2x+2x+x=360
So x = 30 degrees
So the five external angles are 120 °, 90 °, 60 °, 60 ° and 30 °
So the five internal angles are 60 °, 90 °, 120 °, 120 ° and 150 °

The degree ratio of each outer angle of a Pentagon is 2:3:4:5:6. Find the degree of each inner angle of the Pentagon

360*2/2+3+4+5+6=36 180-36=144 360*3/2+3+4+5+6=54 180-54=126 360*4/2+3+4+5+6=72 180-72=108 360*5/2+3+4+5+6=90 180-90=90 360*6/2+3+4+5+6=108 180-108=72

The degree ratio of the five outer angles of a Pentagon is 1:2:3:4:5. The degree ratio of the five inner angles of the Pentagon is 1:2:3:4:5

The outer angle is 24 48 72 96 120, and the inner angle is 156 132 108 84 60, so the degree ratio is 13:11:9:7:5

Simplify the algebraic formula: [(A & sup2; + B & sup2;) / (A & sup2; - B & sup2;) / / 2Ab / (a-b) (a + b) & sup2;], and then evaluate a and B randomly

The original formula = (A & sup2; + B & sup2;) / (a + b) (a-b) × (a-b) (a + b) & sup2. / 2Ab
=(a²+b²)(a+b)/2ab
Let a = 1, B = 2
Then the original formula = (1 + 5) (1 + 2) / 2 × 1 × 2 = 9 / 2