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In the complex plane, which quadrant is the point corresponding to complex number (1-I) / I?
=i(1-i)/i²
=(i-i²)/(-1)
=(1+i)/(-1)
=-1-i
The corresponding point is (- 1, - 1)
third quadrant
The complex z = (M & # 178; - 4) + (M & # 178; - 2m-8) I, where the point corresponding to (m ∈ R) is in the fourth quadrant, then M is in the range of value
Because the real part of the point in the fourth quadrant is positive and the imaginary part is negative,
The system of inequalities can be obtained: M & # 178; - 4 > 0, M & # 178; - 2m-8 < 0,
(m+2)(m-2) > 0 ,(m+2)(m-4) < 0 ,
M < - 2 or M > 2, - 2 < m < 4,
Therefore, the range of M is 2 < m < 4
Given x + Yi = 1, where x and y are real numbers, in the complex plane, find the set of points representing complex x + Yi
x=1,
y=0
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