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A certain market bought a batch of clothes worth 80000 yuan. When the price of each piece was 280 yuan, 150 pieces were sold. In order to promote sales, the shopping mall decided to reduce the price, but hoped to get back the cost when another 200 pieces were sold. So how much yuan can the clothing store reduce the price at most?
Suppose the clothing is reduced by X Yuan, 200 × (280-x) is greater than or equal to 80000-280 × 150, and X is less than or equal to 90. Therefore, the maximum reduction is 90 yuan
1. We know the equation (m-2) x + 3 = 11-3m about X, when m takes what value
(1) X is greater than 0
(2) X is less than 0
(3) X is not greater than 2
2. Given that the solution set X of inequality half (X-5) - 2 is greater than half (AX + 2) is greater than 2, try to find the value range of A
3. Given the system of equations about X, y {X-Y = a + 3; 2x + y = 5a, if x is greater than y, find the value range of A
4. Given the inequality system {x + 9 is less than 5x + 1; X is greater than m + 1, then what is the value of M,
(1) There is no solution to the system of inequalities
Before 11 o'clock! Answer~
1.(m-2)x=8-3m
If M = 2, then the equation obviously does not hold, so m ≠ 2
So x = (8-3m) / (m-2)
(1)(8-3m)/(m-2)>0
So (3m-8) (m-2) 8 is x > 2
And x > m + 1
No matter what the value of M is, it is impossible for the system of inequalities to have no solution
The math problem (solved by inequality) will be solved now
If there are 7 students in a group, there will be 18 more. If there are 10 students in each group, there will be less than 10 students in one group. Find out the number of possible groups and the number of students in the group
The number of possible groups is X
﹛7x+18≥10(x-1)+1 x≤9
7x+18＜10x x＞6
∴6＜x≤9
X is 7,8,9
When x = 7, the number of students participating in the group is 49 + 18 = 67
When x = 8, the number of students participating in the group is 7 × 8 + 18 = 74
When x = 9, the number of students participating in the group is 7 × 9 + 18 = 81
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