2X square + 3x-2 = 0 (x is an integer)

2X square + 3x-2 = 0 (x is an integer)


2X square + 3x-2 = (2x-1) (x + 2) = 0
So x = 1 / 2 or x = - 2



2X ^ 2-3x-2 = 0 find x
When x takes what number, the value of the following fraction is zero 2x ^ 2-3x-2 / x + 2


The factorization is: (X-2) (2x + 1) = 0
Then: x = 2 or x = - 1 / 2



3 ^ (2x) = 4 ^ (3x-1)


3^(2x)=4^(3x-1)
2xlg3=2(3x-1)lg2
xlg3=3xlg2-lg2
3xlg2-xlg3=lg2
x(lg8-lg3)=lg2
xlg(8/3)=lg2
x=lg2/lg(8/3)