To solve it with a quadratic equation of one variable, as follows, we need the equation and the answer 1. A company sold 200 computers in August and 242 computers in October. What is the average monthly growth rate in these two months? 2. If the square of X - 2 (M + 1) x + m square + 5 is a complete square, then M =? 3. Cut a square with 5cm side length from each corner of the rectangular iron sheet, and then fold it up to make a box without cover. The length of the iron sheet is twice the width, and the volume of the box is 1.5dm square, then the length of the iron sheet is equal to? The width is equal to? 4. If the ratio of the two right sides of a right triangle is 8:15 and the length of the hypotenuse is 6.8cm, then the area of the right triangle is equal to? 5. There is a 60 m long and 40 m wide rectangular lawn. A small rectangular flower bed should be opened in the middle of the lawn to make the width of the lawn around the lawn the same, and make the area of the flower bed account for half of the area of the lawn around the lawn?

To solve it with a quadratic equation of one variable, as follows, we need the equation and the answer 1. A company sold 200 computers in August and 242 computers in October. What is the average monthly growth rate in these two months? 2. If the square of X - 2 (M + 1) x + m square + 5 is a complete square, then M =? 3. Cut a square with 5cm side length from each corner of the rectangular iron sheet, and then fold it up to make a box without cover. The length of the iron sheet is twice the width, and the volume of the box is 1.5dm square, then the length of the iron sheet is equal to? The width is equal to? 4. If the ratio of the two right sides of a right triangle is 8:15 and the length of the hypotenuse is 6.8cm, then the area of the right triangle is equal to? 5. There is a 60 m long and 40 m wide rectangular lawn. A small rectangular flower bed should be opened in the middle of the lawn to make the width of the lawn around the lawn the same, and make the area of the flower bed account for half of the area of the lawn around the lawn?

① 200 (1 + x) & 178; = 242 1 + x = ± 1.1, x = 0.1, x = - 2.1 (round)
② If X & # 178; - 2 (M + 1) x + M & # 178; + 5 is a complete square, then for the equation x & # 178; 2-2 (M + 1) x + M & # 178; + 5 = 0, the two roots are equal
△=[2(M+1)]²-4(M²+5)=0
M=2
③ The original width is x and the length is 2x
5（x-10）（2x-10）=1500
x=20,2x=40
④ Using Pythagorean theorem to calculate two right angle sides, and then the triangle area formula
⑤ Lawn width x
（60-2x）（40-2x）=800
x=10

Just list the equations,
The table top is 160cm long and 100cm wide. My mother is going to design a tablecloth, which is twice the area of the table top and has the same width of the edge hanging down all around. My mother wants to find out the width of the edge hanging down all around. Can you help my mother solve this problem?

Set the width of the edge x cm,
(100+2x)*(160+2x)=160*100*2

How to better find the third grade mathematics equating the series of equations?

It's very simple, first, read the question, write down the useful number to one side or draw a short line with a pencil, second, set the unknown quantity, and list the equation step by step according to the meaning of the question

Several mathematics problems of grade one in junior high school,
1: If Y1 = 2x + 1, y2 = 3-x, then=____ When, Y1 = Y2
2: If a store sells a commodity with a purchase price of 1500 yuan at a 20% discount on the list price, it can still make a profit of 280 yuan. If the list price is set at x yuan, the equation can be__ And the solution is X=____
3: If 2a and 1-A are opposite to each other, then a=____ If 2a is equal to 1-A, then a=____ If 2a is greater than 1-A, then a=______ If 2a is 2 less than A-1, then a=_____

1: If Y1 = 2x + 1, y2 = 3-x, then=____ When Y1 = y22x + 1 = 3-x, x = 2 / 32: if a store sells a commodity with a purchase price of 1500 yuan at a 20% discount on the price, it can still make a profit of 280 yuan. If the price is set at x yuan, the equation can be__ And the solution is X=____ 0.8x + 280 = 1500x = 15253: if 2a and 1-A are opposite to each other, then a=____ ;...

(1) It is known that the solution of the equation 5x + 2A = 0 about X is 2 smaller than that of - 2 / 3x + 6 = 0, so we can find the value of A
(2) We know the equation MX & # 178; + NX = 0
① If the solution of the equation is all real numbers, find the value of M & # 178; + n & # 178
(3) Xiao Ming has set up a three-year education savings (the annual interest rate for the three-year period is 2.75%). After three years, he can withdraw 5405 yuan (excluding interest tax). How many yuan has he just deposited?

(1) The solution of - 2 / 3x + 6 = 0 is: x = 9, so the solution of 5x + 2A = 0 is: x = 7, so 35 + 2A = 0, a = - 35 / 2
(2) Because the solution of the equation is all real numbers, so, M = 0, n = 0. So, M & # 178; + n & # 178; = 0
(3) Let X be saved at the beginning
（1+2.75%）^3X=5405
X=5405/（1+2.75%）^3.

1. A workshop processes a batch of parts. The original plan is to process 100 parts per day, which can be completed as scheduled. After improving the technology, it processes 10 more parts per day. As a result, it is completed two days ahead of schedule. How many parts are there? How many days is the original plan to complete?
2. When a ship runs between two wharves, it takes 4 hours downstream and 5 hours upstream. If the current velocity is 2 km / h, calculate the distance between the two wharves
3. A trainer plane can fly in the air for 2 hours at most, with an exit speed of 480 km / h and a return speed of 520 km / h. how many km should this plane return?
4. A and B are running from a and B. A starts 15 minutes earlier than B. the speed ratio of a and B is 2:3. When a and B meet, a runs 6 kilometers less than B. It is known that B runs for 1 hour and 30 minutes. Find out the distance between B and B
5. The total workload of the four workers in group A in March is 20 pieces more than 4 times of the per capita quota in this month, and the total workload of the five workers in group B in March is 20 pieces less than 6 times of the per capita quota in this month
(1) If the actual per capita workload of the two groups of workers in this month is equal, how many pieces is the per capita quota in this month?
(2) If the actual per capita workload of group a workers in this month is 2 pieces more than that of group B, then what is the per capita quota of this month?
(3) If the actual per capita workload of group A is 2 pieces less than that of group B, how many pieces is the per capita quota of this month?

1. X, y days
X/100=Y
X/(100+10)=Y-2
X=2200
Y=22
2. Distance x km
X/4-2=X/5+2
X=80
3. Fly x kilometers
X/480+X/520=2
X = 499.2km
Others think for themselves

1. Given that the equation (︱ - 4) - (A-4) x &; ‐ & sup3; + 5 = 0 is a one variable linear equation about X, find the solution of the equation a (X-2) + (n / 3) x = 5 about X
2. In the equation 3mx = (2m-1) x + 1 of X, when m is an integer, the solution of the equation is a positive integer
3. We know that the equation of X, X (2x + b) = 12x + 5, has innumerable solutions

Because it is a univariate linear equation of X, so the degree is one, then n-3 = 1, n = 4 and this is a univariate linear equation of X, then no other unknowns can appear. Therefore, the elimination a is not equal to 4 and the absolute value a = plus or minus 4, so a = - 4 brings x = nine eighths
2. We simplify (M + 1) x = 1, X is a positive integer, so m = 0
You've got the wrong number. I didn't study in junior high school

It is known that the bivariate linear equation 2x + y = 6. (1) when the values of X and y are equal, find the solution of the original equation; (2) when the sum of two times of X and Y is - 3, find the solution of the original equation

(1) When the values of X and y are equal, i.e
x=y
Substituting: 2x + y = 6
2y+y=6
y=3
Substituting 2x + y = 6:
2x=6-3
x=3/2
When the values of X and y are equal: 2x + y = 6, the solution of the original equation is x = 3 / 2, y = 3
(2) When the sum of two times of X and Y is - 3, that is:
x+2y=-3①
2x+y=6②
①×2-②：3y=-12
y=-4
Substituting ①: x = 5
(2) When the sum of two times of X and Y is - 3, the solution of the original equation is x = 5, y = - 4

X / 2 = Y / 3 = Z / 4 2x-y + 3Z = 26 quadratic equation with 2 variables

X/2=Y/3=Z/4=K
X=2K,Y=3K,Z=4K
∵2X-Y+3Z=26
If we take the above three formulas into account, we can get the following results:
4K-3K+12K=26
13K=26
K=2
∴X=4,Y=6,Z=8

The nonnegative integer solution of quadratic equation 2x + y = 5 is——————————————

y=5-2x>=0
So 2x