Why does the equation 1 / X-1 + m / X-2 = 2m + 2 / x ^ 2-3x + 2 have an increasing root when m is a value? When the value of M is what, the solution of the equation 2 / x + 1 + 5 / 1-x = m / x ^ 2-1 will produce increasing roots? If the equation X-2 / X-5 = m / X-5 + 2 about X has no real root, find the value of M. If the fractional equation k-1 / x ^ 2-1-1 / x ^ - x = K-5 / x ^ 2 + X has an increasing root x = - 1, what is the value of K?

Why does the equation 1 / X-1 + m / X-2 = 2m + 2 / x ^ 2-3x + 2 have an increasing root when m is a value? When the value of M is what, the solution of the equation 2 / x + 1 + 5 / 1-x = m / x ^ 2-1 will produce increasing roots? If the equation X-2 / X-5 = m / X-5 + 2 about X has no real root, find the value of M. If the fractional equation k-1 / x ^ 2-1-1 / x ^ - x = K-5 / x ^ 2 + X has an increasing root x = - 1, what is the value of K?

Multiply by (x-1) (X-2)
x-2+m(x-1)=2m+2
Increasing the root means that the common denominator is 0
(x-1)(x-2)=0
x=1,x=2
x=1
Substituting X-2 + m (x-1) = 2m + 2
-1=2m+2
m=-3/2
x=2
Substituting X-2 + m (x-1) = 2m + 2
0+m=2m+2
m=-2
m=-3/2,m=-2

The cube of (x's square-4y's Square) - (x + 2Y) 2, (x's square-y's Square) (x + y) - (X-Y)

(x + 2Y) (x-2y) - # 178; = (x + 2Y) (x-2y) - # 178; = (x + 2Y) (x-2y-x-2y) = - 4Y (x + 2Y) (x-y-y) (x + y) = (X-Y) = (x + y) (x + y) - (X-Y) = (X-Y) [(x + y) & # 178; - (X-Y) & # 178;] = (X-Y) (x + y + X-Y) = (x + y) = (x + y) & # 178;] = (X-Y) = (x + y + X-Y) = (x + y) = (x + y) = (x + y) = (x + y) = (x + y) = (x + y) = (x + y) =

5y-4.5 = 2Y to solve the equation

The original formula 5y-4.5 = 2Y
5y-2y = 4.5
Simplify 3Y = 4.5
The solution is y = 1.5

The equation is solved by {x + 2Y = 10 {x + 1 / 3 = 2Y + 2 / 5-1,
{x＋2y＝10
{x＋1/3＝2y＋2/5－1

+2/5-1=-3/5
x+1/3=2y-3/5
x=2y-3/5-1/3
x=2y-14/15
4y-14/15=10
4y=10+14/15
y=41/15
x=150/15-82/15
x=67/15