How many powers of X will the m power of (- 1 / x) be equal to?

How many powers of X will the m power of (- 1 / x) be equal to?


Is the m-th power of (- 1) multiplied by the negative m-th power of X



We know that the a power of 3 is equal to 5, the B power is equal to a, and the reciprocal of a plus the reciprocal of B is equal to 2


From the power of a of 3 = a, a = log3 ^ A is obtained. Similarly, B = log5 ^ a (a > 0) 1 / A + 1 / b = loga ^ 3 + loga ^ 5 = 2 (formula for changing bottom) ∧ loga ^ 15 = 2, a = 15 ∧ a = root 15



Given that y = f (x) is an increasing function in the domain (- 1,1), and f (1-A) < f (3a-1), then the value range of a is
The sooner the better


Y is an increasing function in the domain because f (1-A)



Given that the zero point of function f (x) = lgx + 2x-5 is in the interval (n, N + 1), then the value of integer n is______ .


From the analytic expression of the function, we can get that the function is an increasing function on (0, + ∞), and f (2) = lg2-1 < 0, f (3) = Lg3 + 1 > 0, so f (2) f (3) < 0. According to the judgment theorem of function zero point, we can get that the function has zero point on the interval (2,3)



The known function f (x) = lgx + x-3 means that the function has a unique zero point in the interval (2,3)


Y = lgx is monotonically increasing on (0, + ∞) and elementary basic function (continuous function). Y = x is monotonically increasing on (0, + ∞) and elementary basic function, so f (x) = lgx + x-3 is continuous and monotonically increasing on (0, + ∞)
We can find out f (2) and f (3) and find f (2) 0. From the above, we can see that f (x) has a unique zero point in the interval (2,3)
Note that if f (x) is discontinuous or not monotonically increasing, this method is not applicable!



Given two functions f (x) = 2x ^ 2 + 1, G (x) = 3x, define function f (x) = f (x) + G (x) + 1, (f (x) > G (x)); f (x) / g (x), (f (x) ≤ g (x))
(1) The expression of finding f (x)
(2) What is the value of X? What is the minimum value of F (x)?


1) Let 2x ^ 2 + 1 > 3x, then (x-1) (2x-1) > 0, namely x1,
So f (x) = {2x ^ 2 + 3x + 1 (x1); (2x ^ 2 + 1) / (3x) (1 / 2)



1. What is the interval of the zeros of the function f (x) = 2 ^ x + X?
2. On the two real number roots X1 and X2 of the equation x ^ 2 + (a + 1) x + A + B + 1 = 0 (a ≠ 0, a and B belong to R), if 0 < X1 < 1 < X2, then the value range of B / A is?


F (x) is an increasing function
f(-1)=1/2-10 f(1)0
2a+b+3-1-a b-1-a b



Let f (x) = (M + 1) x to the second power + MX-1 be even function, then f (2) =?


F (x) = (M + 1) x ^ 2 + MX-1 is even function
Then f (- x) = f (x)
That is, (M + 1) x ^ 2 + MX-1 = (M + 1) x ^ 2-mx-1
-m=m
m=0
The original formula F (x) = x ^ 2-1
f (2)=3



F (x) = the power of [- 2 (m) + m + 3] of X (M belongs to Z) is even function, f (3)


f(3)0
2m²-m-3



Given that f (x) is an even function and f (x) = f (x + 4), if - 2 is less than or equal to X and less than or equal to 0, f (x) = 2 ^ x, then f (2009)=


Because f (x) = f (x + 4), f (2009) = f (1)
And f (x) is even function, f (2009) = f (1) = f (- 1)
Again - 2