The factorization of a (AB + BC + AC) - ABC

The factorization of a (AB + BC + AC) - ABC

a(ab+bc+ac)-abc
=a(ab+ac)+abc-abc
=a(ab+ac)
=a^2(b+c)

⑤ . a (AB + BC + AC) - ABC for results (factorization)

The original formula = A & # 178; B + ABC + A & # 178; c-abc
=a²b+a²c
=a²(b+c)

Can AB + AC + BC be factorized

Let me answer for you!
Three words: No
Because it has no common alphabet
For example. A has only the first and the second, but the third doesn't
B only the first and the third have, but the second does not
C only the second and third have and the first doesn't
So, that is to say, there must be a common letter to decompose
See?
Let's choose a couple