In a 40 cm long and 20 cm wide cuboid water tank, a cuboid iron block is placed, and the water surface rises by 2 cm It is known that the length and width of the iron block are both 10 cm, and the height of the iron block is how many cm

In a 40 cm long and 20 cm wide cuboid water tank, a cuboid iron block is placed, and the water surface rises by 2 cm It is known that the length and width of the iron block are both 10 cm, and the height of the iron block is how many cm


In a cuboid water tank 40 cm long and 20 cm wide, a cuboid iron block is put in, and the water surface rises by 2 cm. It is known that the length and width of the iron block are 10 cm, and how many cm is the height of the iron block
40x20x2÷(10x10)
=1600÷100
=16 cm
So it's 16 centimeters
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A cuboid glass fish tank without a cover, 0.5m long, 2DM wide and 30cm high. How many square meters of glass should be used to make the fish tank? The maximum amount of glass in the bathtub
How many liters of water can the bathtub hold at most?


A cuboid glass fish tank without cover, 0.5m in length, 2DM in width and 30cm in height. How many square meters of glass should be used to make the fish tank? How many liters of water can be held in the bathtub?
The results are as follows
2dm==0.2m,30cm==0.3m
The surface area of fish tank is: 0.5 * 0.2 + 0.5 * 0.3 * 2 + 0.2 * 0.3 * 2 = = 0.52 m2
The volume of the fish tank is: 0.5 * 0.2 * 0.3 = = 0.03 cubic meters
1 liter = = 1 cubic decimeter
So, 0.03 cubic meters = = 30 cubic decimeters = = 30 liters
A: this fish tank needs at least 0.52 square meters of glass. The maximum amount of water in the bathtub is 30 liters



A rectangular water tank is 1m long, 0.8m wide, 0.5m high, and the water is 40cm high. After a rectangular iron block with a length of 0.8m and a width of 0.5m is put in, the water is just full of the tank, and the height of the iron block is calculated


Analysis: cuboid tank volume = water volume + iron volume (cuboid volume = length x width x height)
Water height 40 cm = 0.4 m
Suppose the high position of the iron block is x meters
1×0.8×0.5=1×0.8×0.4+0.8×0.5×X
The solution is x = 0.2
A: the height of the iron block is 0.2m (20cm)